From: SIM KM (04mgls@gmail.com)
Date: Tue Jun 13 2006 - 22:58:09 ART
hi all,
I thought the original solution is correct.
Sami,
to check 0.0.0.0 first octet with an inverse mask of 254.255.255.255
would allow us to only filter out the wanted even octect.
Take for example, 192.168.10.2 mask 255.255.255.0
That means we want to have the first 3 octects check as 192.168.10
If we only want to check odd bytes from the first octect,
Network 00000001
mask 00000001
with ACL inverse mask;
Network 00000001
Inv mask 11111110
Therefor I think the answer from the book is correct.
Thanks
On 6/14/06, Bob Sinclair <bsinclair@netmasterclass.net> wrote:
>
> Sami,
>
> I agree with you. The writer should either change the access-list to a
> "deny", or change the prefix to zero in the last bit of the first octet.
>
> HTH,
>
>
> Bob Sinclair
> CCIE #10427, CCSI 30427
> www.netmasterclass.net
>
> ----- Original Message -----
> From: Sami
> To: Cisco certification
> Sent: Tuesday, June 13, 2006 6:30 PM
> Subject: Access List
>
>
> Group,
>
> One of task says filter out all odd network from first octet , and
> solution
> given is
>
> ip access list 1 permit 1.0.0.0 254.255.255.255
>
> why first octet of network is 1 ?
>
> shouldn't it be 0.0.0.0 ( any ) 254.255.255.255 ?
>
> Thanks
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
This archive was generated by hypermail 2.1.4 : Sat Jul 01 2006 - 07:57:32 ART