From: WorkerBee (ciscobee@gmail.com)
Date: Tue Jun 06 2006 - 07:50:49 ART
Frame Relay largest Tc = 1/8 sec
Hence assuming Tc = 125 msec
Bc = 128k/8
= 16k
Be = 0.25 * Bc (Based on requirement)
= 4k.
HTH
On 6/6/06, Leigh Harrison <ccileigh@gmail.com> wrote:
> Hey there Andi,
>
> CIR is in bits, Bc is in bytes
>
> 128,000 / 4 = 32,000 _bits_ per interval
>
> 32,000 / 8 = 4,000 _bytes_ per interval
>
> Hope that helps a bit,
>
> LH
>
> Andi Bennett wrote:
> > Dear group.
> > Being a bit crap at FRTS can somebody explain the answer to the Lab 1 7.2 question.
> >
> > 128K CIR and allow for 1/4th for burst.
> >
> > How does this come up with bc = 4000 ?
> >
> > Am I missing something here?
> > Cheers
> > A.
> >
> >
> >
> > Send instant messages to your online friends http://uk.messenger.yahoo.com
> >
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