From: Nick Griffin (ngriffin@sio.midco.net)
Date: Fri May 05 2006 - 12:18:27 ART
They just used the default reference bandwidth 108 divided by the
bandwidth of the interface, in this case 1024, or 1024000. This gives
you 97.65625.
Melwani, Manoj J wrote:
> Can some explain?
>
> Questions says:
>
> "The frame rely circuit between R3 and R4 has a provisioned rate of 1024kbps, while the circuit between R3 and R5 is only provisioned at 512kbps. Ensure that R3 takes this into account when computing OSPF metrics on this segment"
>
> Solutions say:
>
> R3:
>
> router ospf 1
> network 150.1.3.3 0.0.0.0 a 3457
> network 154.1.0.3 0.0.0.0 a 3457
> nei 154.1.0.5 cost 195
> nei 154.1.0.4 cost 97
>
> Can someone explain how did they calculate cost in the above solution? I mean how they got 195 and 97?
>
> thanks,
> Manoj.
>
> Manoj J. Melwani
> Citigroup - Extranet Network Integration
> Phone: (212) 291-3189
> Email: manoj.j.melwani@citigroup.com
>
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