From: Scott Morris (swm@emanon.com)
Date: Wed Apr 05 2006 - 23:20:58 GMT-3
Be is a completely separate number from Bc. So if you are looking at a peak
value of 128K, that would be Bc + Be. Therefore, Be would also equal 8000
bits/Tc.
While the math may end up being quite simple, sometimes it takes a little
staring and head-scratching to get the electrons flowing in the right
direction!
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE
#153, CISSP, et al.
IPExpert CCIE Program Manager
IPExpert Sr. Technical Instructor
swm@emanon.com/smorris@ipexpert.com
http://www.ipexpert.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Mike
Baily
Sent: Wednesday, April 05, 2006 10:14 PM
To: ccielab@groupstudy.com
Subject: traffic shaping question
Sorry to ask this seemingly stupid question, but I am sitting here looking
at two books telling me two different things and now I am doubting myself.
( and I have a quickly approaching lab date too, so I have started panic
mode a little bit )
The questions (both are very similar):
Configure a CIR of 64000 bps but allow traffic to burst to the line speed
of 128.
Assuming the Tc is .125, bc would be 8000, so what would the Be be?
The first book says 64000 (the difference between CIR and line speed)
Then the other says Be would be 16000 (essentially what would be sent per
time intereval.
I had always thought it was the first one but I just wanted to make sure.
Thanks
---------------------------------
Yahoo! Messenger with Voice. PC-to-Phone calls for ridiculously low rates.
This archive was generated by hypermail 2.1.4 : Mon May 01 2006 - 11:41:56 GMT-3