InternetworkExperts Lab 3 Vol III Task 5.4 and Task 5.5

From: Victor Cappuccio (cvictor@protokolgroup.com)
Date: Wed Mar 22 2006 - 16:54:07 GMT-3


Hola ...

I have a doubt, about the IEWB solution in Lab 3 Vol III Task 5.4 and
Task 5.5
In Task 5.4 R1 also advertise R2 Vlan 2 Route route to R5, so IMHO a
Distribute list should be applied to the outbound of R1 to R5 ??
Or it does not matter?

R1#
router bgp 100
***
neighbor 136.1.15.5 distribute-list 2 out
***

access-list 2 deny 136.1.2.0 0.0.0.255
access-list 2 permit any

Rack1R5#show ip bgp 136.1.2.0
BGP routing table entry for 136.1.2.0/24, version 5
Paths: (1 available, best #1, table Default-IP-Routing-Table)
  Advertised to non peer-group peers:
  4.4.4.4 136.1.15.1 136.1.57.7
  300 300 300
    136.1.245.2 from 136.1.245.2 (2.2.2.2)
      Origin IGP, metric 0, localpref 100, weight 100, valid, external, best

And for Task 5.5 In my crazy world I did the following

R2#
router bgp 300

***
neighbor 136.1.245.5 route-map PREPREND:AS:PATH out

****

Rack1R2#show route-map PREPREND:AS:PATH
route-map PREPREND:AS:PATH, permit, sequence 10
  Match clauses:
  Set clauses:
    as-path prepend 300 300
  Policy routing matches: 0 packets, 0 bytes

But the solution show the use of conditional Advertisement but to be
honest, right now I can not see why the network 136.1.23.0/24 is
advertised in BGP

Thanks for your invaluable input

Victor.



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