From: Jonathan Stevens (jonathanstevens.net@googlemail.com)
Date: Sat Jan 14 2006 - 15:26:04 GMT-3
I talked to NMC about that question, check the discussion forum for the lab.
Basically,
bandwidth 4 6 5 5
This set the ratio between four queues (in terms of bandwidth)
You could have written...
bandwidth 20 30 25 25
It's the same.
Next they map the cos values to the four queues.
Then, it kinda messes up, I think they're going to adjust the question.
When you set
priority-queue out
this tells the switch to prioritise queue 4. Queue 4 is now the expidite
queue. It is serviced until it is empty and then the other queues are
serviced. So in the example anything with COS 3 is serviced first.
However, when you use this, it effectively changes
bandwidth 4 6 5 5
to
bandwidth 4 6 5 0
So queues 1,2 & 3 now have 26.7%, 40% and 33.3% of the bandwidth WHEN
THERE IS NOTHING IN QUEUE 4.
Bill.McKenzie@bisys.com wrote:
>Here is the requirement :
>Cos-3 must be sent of everything else and match the following cos values to
>according bandwidth.
>
>Cos 3 = 25%
>CoS 6,7 = 20%
>CoS 0,1,2 = 30%
>CoS 4,5 = 25%
>
>Here is the solution:
>
>wrr-queue bandwidth 4 6 5 5
>wrr-queue cos-map 1 6 7
>wrr-queue cos-map 2 0 1 2
>wrr-queue cos-map 3 4 5
>wrr-queue cos-map 4 3
>priority-queue out
>
>
>I don't understand the values in the wrr-queue bandwidth command and trying
>to look at the doc cd is just confusing me more. Can anyone point me to a
>better explanation of how the values were estimated?
>
>Thanks,
>Bill
>
>
>
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