From: Victor Cappuccio (cvictor@protokolgroup.com)
Date: Sun Oct 30 2005 - 02:23:21 GMT-3
Hello,
If one of the questions is like in a Frame Relay scenario all frames should be
marked with the DE at 128 Kbps (SO that would be my Line between Bc and Be the
CIR Right?) and all frames should be discarded at 256Kbps (THIS confuses me
with policing / Maybe is an English Problem but I guess that by reading the
whole problem, should redirect me to think in shaping / ANYWAY this should be
the Arate right?), when a BECN is received it should be guaranteed 64 Kbps
(THAT should be my MinCir), use the lowest Time Interval (THAT should be 10ms
/ I Think that this is related to the serialization delay and all that stuff)
So if Shaping is correct, I wish please to know if the logic below is right
Ok so the formulas that I know are:
Be = (AR - CIR ) * Tc / 1000
Bc = (Cir*tc)/1000
So the variables that I have are:
AR = = 256000
CIR == 128000
MinCir == 64000 (This is the "guaranteed" by the SP right? And all the logic
behind the 25% drop per BECns)
Be == [(2560000 - 128000) * 10]/ 1000
Bc == (128000 * 10) / 1000
http://www.cisco.com/warp/public/125/traffic_shaping_6151.html
interface Serial0/0
no ip address
encapsulation frame-relay
no fair-queue
frame-relay traffic-shaping
interface Serial0/0.1 point-to-point
ip address 10.1.1.1 255.255.255.0
frame-relay interface-dlci 16
frame-relay class cisco
map-class frame-relay cisco
frame-relay cir 128000
frame-relay mincir 64000
frame-relay adaptive-shaping becn
frame-relay bc 1280
frame-relay be 1280
This 2 Values are added right to get the Line Rate in every Tc in a second?
Thanks for the Help
--- Victor Cappuccio cvictor@protokolgroup.com ..O. ....O OOO
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