From: Victor Cappuccio (cvictor@protokolgroup.com)
Date: Thu Oct 13 2005 - 05:17:06 GMT-3
Hello Simon, You are very right, but the problem here is that this PC
(R1) is on a different subnet, than R2, and original question was that
R1 needs a way to ping all R3 Interfaces..
So
R1 Eht0/0 IP Address 10.50.50.1/29
Eth0/0 IP Address 10.0.0.1/8 Secondary
ARP R3 Int X n/n MAC-ADD R2 ETH
================================
Ethernet Media
===================================
R2 Eth0/0 IP Address 10.60.60.2/29
redistribute mobile to OSPF (This would help R3 with the return traffic)
===================================
Cloud Running OSPF
===================================
R3
So maybe I think that I have to change the Subject of this email, to LAM
Question.
Thanks
Victor
simon hart wrote:
>I am not sure why you are all looking into things like LAM & ODR etc to
>accomplish what is a relatively simple task.
>
>The original question was the R1 does not run any routing protocol but to
>have connectivity to all of R3.
>
>With such a question look for the obvious first. R1 must behave like a
>host, such as PC. PC's do not run routing protocols but should be able to
>ping everything within it's associated network, it does this without LAM/ODR
>etc etc. So how does a PC gain this connectivity, well it has a default
>gateway, that is an associated device that will find the path for it (AKA
>router).
>
>So we need to make R1 behave like a PC. Simple turn off ip routing
>
>no ip routing
>
>As soon as that command is entered the router will never ever run a routing
>protocol.
>
>Okay now how to packets get out of the router, easy:-
>
>ip default-gateway R2's IP address.
>
>This is really the only answer that is being looked for. Looking into
>anything else is playing with semantics and rather confusing, and I am sure
>does not help with learning
>
>HTH
>
>Simon
>
>-----Original Message-----
>From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
>De Witt, Duane
>Sent: 13 October 2005 08:07
>To: Javier Tomi
>Cc: Cisco certification
>Subject: RE: Router with out any routing Protocol
>
>
>Hi
>
>I think it would be best to do things in steps here. I'm not disputing how
>LAM works here, but we need layer 3 connectivity with some sort of routing
>running between R1 and R2 before we can even start thinking about LAM. If R1
>and R2 are in different subnets we have a straight forward layer 3 problem
>which needs to be resolved before adding complex things like LAM on top of
>it.
>
>-----Original Message-----
>From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
>Javier Tomi
>Sent: 13 October 2005 08:43 AM
>Cc: 'Cisco certification'
>Subject: Re: Router with out any routing Protocol
>
>Correct me if I am wrong, but with LAM There is no need of both routers
>to be on the same network. R2 will install a host route to the IP
>address of R1, and due to proxy-arp configured on R2, it will response
>to ARP request from R1 searching his default gateway. Of course, R2 will
>need a route to R1 network by some means.... Isn't it?
>
>
>
>
>Victor Cappuccio wrote:
>
>
>
>>OK, Thanks in advanced.. Any other comments
>>
>>
>>De Witt, Duane wrote:
>>
>>
>>
>>
>>
>>>No, R2 will still be looking for something in it's own subnet as far
>>>as I know. I'll lab it up later and check, just busy with IEWB at the
>>>moment.
>>>
>>>
>>>
>>>------------------------------------------------------------------------
>>>
>>>*From:* Victor Cappuccio [mailto:cvictor@protokolgroup.com]
>>>*Sent:* 13 October 2005 08:28 AM
>>>*To:* De Witt, Duane
>>>*Cc:* Cisco certification
>>>*Subject:* Re: Router with out any routing Protocol
>>>
>>>
>>>
>>>Hello Duane, Many Thanks for your replys, maybe I'm saying something
>>>stupid here, but R1 haves a 10.0.0.1 /8 as a secondary address..
>>>And by adding this I will cover all subnets, right?
>>>
>>>Thanks again
>>>Victor.
>>>
>>>
>>>
>>>De Witt, Duane wrote:
>>>
>>>R1 and R2 aren't in a common subnet, so I'm not sure what you are
>>>trying to achieve?
>>>
>>>
>>>
>>>------------------------------------------------------------------------
>>>
>>>*From:* Victor Cappuccio [mailto:cvictor@protokolgroup.com]
>>>*Sent:* 13 October 2005 08:19 AM
>>>*To:* De Witt, Duane
>>>*Cc:* Cisco certification
>>>*Subject:* Re: Router with out any routing Protocol
>>>
>>>
>>>
>>>I wish to have a CCIE rack to play but for now, I just have a 3640
>>>gift from a good Friend... (I know that only with one router would
>>>not let me understand anything but it's cool to check weird
>>>configurations or command parameters / Do someone from the other side
>>>of the world (My time zone is GMT -4) have a rack that does not uses
>>>in the night and be so generous to share it? :-) )
>>>
>>>R1:
>>>interface FastEthernet0/0
>>>ip address 10.0.0.1 255.0.0.0 secondary
>>>! Thats why I told about to create a secondary address - I did not
>>>finish the idea when I sent the email / I Think I'm getting Crazy with
>>>all this stuffs.. Sorry for that
>>>ip address 10.50.50.2 255.255.255.248
>>>speed 100
>>>full-duplex
>>>
>>>R2:
>>>interface FastEthernet4/0
>>>ip address 10.60.60.1 255.255.255.248
>>>ip mobile arp access-group 2
>>>duplex full
>>>
>>>
>>>access-list 2 permit 10.50.50.2
>>>
>>>De Witt, Duane wrote:
>>>
>>>I don't think this scenario would work. LAM would require R1 and R2
>>>
>>>ethernet to be in the same subnet, however it will allow users on R1
>>>
>>>ethernet to be on a subnet allocate somewhere else in the network.
>>>
>>>
>>>
>>>If R1 and R2 ethernet are in different subnets how will you get
>>>
>>>communication going between the two?
>>>
>>>
>>>
>>>-----Original Message-----
>>>
>>>From: nobody@groupstudy.com <mailto:nobody@groupstudy.com>
>>>
>>>
>[mailto:nobody@groupstudy.com] On Behalf Of
>
>
>>>Victor Cappuccio
>>>
>>>Sent: 13 October 2005 07:50 AM
>>>
>>>Cc: Cisco certification
>>>
>>>Subject: Re: Router with out any routing Protocol
>>>
>>>
>>>
>>>Ok this one was easy, lets change the Scenario a little bit, using the
>>>
>>>same same topology, but now R1 is in a different Subnet than R2, so now
>>>
>>>we need to configure LAM on R2, and Redistributing the mobile into the
>>>
>>>ospf gives R3 the way to get to R1, but what about the return traffic R1
>>>
>>>
>>>
>>>-> R3?
>>>
>>>
>>>
>>>Thanks
>>>
>>>Victor.
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>manoj menon wrote:
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>>On R1#
>>>>
>>>>
>>>>
>>>>no ip routing
>>>>
>>>>!
>>>>
>>>>ip default-gateway <R2-E0-IP_ADD>
>>>>
>>>>!
>>>>
>>>>Either you can advertise the R1-R2 Ethernet subnet in OSPF, or
>>>>
>>>>redistribute, or static route back to R1, and redistribute static into
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>>
>>>>OSPF...
>>>>
>>>>
>>>>
>>>>Comments...
>>>>
>>>>
>>>>
>>>>Regards,
>>>>
>>>>Mnaoj
>>>>
>>>>
>>>>
>>>>*/Victor Cappuccio <cvictor@protokolgroup.com>
>>>>
>>>>
><mailto:cvictor@protokolgroup.com>/* wrote:
>
>
>>>>
>>>> Hello People, consider this Scenario
>>>>
>>>>
>>>>
>>>> 10.1.1.0/24
>>>>
>>>> R1 --- Ethernet --- R2 | Network Cloud Running OSPF | R3.
>>>>
>>>> ---Vlan 50 ----
>>>>
>>>>
>>>>
>>>> You are not allowed to configure any routing protocol on R1, but
>>>>
>>>> one of
>>>>
>>>> the requirements is that R1 should be able to ping any ip address
>>>>
>>>> in R3,
>>>>
>>>> how would you accomplish this? I thought to create a secondary
>>>>
>>>> address
>>>>
>>>> in R1 with an IP Classful Address Mask (10.0.0.1/8) and complete
>>>>
>>>> the ARP
>>>>
>>>> Table for R3 physical interfaces with R2 Ethernet Mac Address
>>>>
>>>> (since R2
>>>>
>>>> knows the complete network).- I Think this could work Ok / Have
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>not
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>> tested yet .. Can you see another was of accomplishing this task?
>>>>
>>>>
>>>>
>>>>
>>>>
>>>> Regards
>>>>
>>>> Victor.
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
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>>>>
>>>>
>>>>
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>>>
>>>
>>>
>>>
>>>
>>>
>>>
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