From: Victor Cappuccio (cvictor@protokolgroup.com)
Date: Fri Oct 07 2005 - 13:50:19 GMT-3
Sorry the AND would be 00000010, so in notepad because of his font would
help you more, not to have those 1 0 no delineated.
So the AND is in the network and the XOR is the MASK
Thanks and sorry for the mistake (as I said, Binary = Computers . We
have the right to Mistake)
Victor Cappuccio wrote:
> Hola Vidhya,
>
> Ok Binary is for computers we are humans, so let the binary belong to
> computers, we do the light part (Thinking)
> This is a TIP:
> Open Notepad
> Open Windows Calc
> Convert Dec -> Binary in the Windows Calc
> Copy it
> Paste it in notepad
>
> So at the end you will have a list of 1 / 0 from all the IP Address,
> lets take the one that Scott did
> 2 00000010
> 10 00001010
> 18 00010010
> 26 00011010
> Now who to calculate de Mask, Use Logical ANDs and Logical XORs from
> this list
> / Just in case you wonder XOR = 1 only if (0X1 | 1X0) and AND = 1 only
> if (1A1)
> Now,
> AND would be 00000000
> XOR would be 00011000
> Copy those values to the windows calc (be sure to be in Bin mode), or
> simple use this rule 128..64..32..16..8..4..2..1
>
> Try that and you will find it very easy to do, because is math .-
>
> HTH
> Victor.
>
>
> Leigh Harrison wrote:
>
>> Vidhya,
>>
>> You're binary is bang on. bit 16 and bit 8 which = 24
>>
>> LH
>>
>> vidhya natarajan wrote:
>>
>>> Scott/Carl,
>>>
>>> Thanks for the reply.. I think the mask shud be .18?
>>>
>>> >2 00000010
>>> >10 00001010
>>> >18 00010010
>>> >26 00011010
>>> >Diff 00011000 = .24 Mask <---- would be a .18 mask isnt it?
>>>
>>> So the final one would be 200.0.1.2 0.0.2.18 ?
>>>
>>> Looking forward for your reply..
>>>
>>> Thanks,
>>> Vidhya
>>>
>>>
>>> On Thu, 06 Oct 2005 Carl Willias wrote :
>>> >Scott you nailed it. I missed the third octet.
>>> >
>>> >CW
>>> >
>>> >----- Original Message ----
>>> > From: Scott Morris <swm@emanon.com>
>>> >To: Carl Willias <mandingo2073@yahoo.com>; Lee Donald
>>> <Lee.Donald@t-systems.co.uk>; Leigh Harrison <ccileigh@gmail.com>;
>>> ccielab@groupstudy.com
>>> >Sent: Thursday, October 06, 2005 10:15:20 AM
>>> >Subject: RE: Double Check access-list
>>> >
>>> >
>>> >200.0.1.2
>>> >200.0.3.2
>>> >200.0.3.10
>>> >200.0.1.18
>>> >200.0.3.26
>>> >200.0.1.10
>>> >200.0.3.18
>>> >200.0.1.26
>>> >
>>> >Third Octet:
>>> >
>>> >1 00000001
>>> >3 00000011
>>> >Diff 00000010 = .2 Mask
>>> >
>>> >Fourth Octet:
>>> >
>>> >2 00000010
>>> >10 00001010
>>> >18 00010010
>>> >26 00011010
>>> >Diff 00011000 = .24 Mask
>>> >
>>> >Remember that the router sees these things simply as strings of 32
>>> bits.
>>> >It's only our little brains that need the dotted-decimal octet
>>> >representations. :)
>>> >
>>> >200.0.1.2 0.0.2.24 mask will give a total of three bits of
>>> difference. 2^3
>>> >yields 8 matches, and we have 8 lines listed.
>>> >
>>> >Scott
>>> >
>>> >
>>> >-----Original Message-----
>>> > From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On
>>> Behalf Of Carl
>>> >Willias
>>> >Sent: Thursday, October 06, 2005 11:02 AM
>>> >To: Lee Donald; Leigh Harrison; ccielab@groupstudy.com
>>> >Subject: Re: Double Check access-list
>>> >
>>> >I think the answer is
>>> >
>>> >200.0.3.2 0.0.0.24
>>> >200.0.1.2 0.0.0.24
>>> >
>>> >CW
>>> >
>>> >----- Original Message ----
>>> > From: Lee Donald <Lee.Donald@t-systems.co.uk>
>>> >To: Leigh Harrison <ccileigh@gmail.com>; ccielab@groupstudy.com
>>> >Sent: Thursday, October 06, 2005 9:05:05 AM
>>> >Subject: RE: Double Check access-list
>>> >
>>> >
>>> >Leigh,
>>> >
>>> >How's it going? Your access-list does work however it also includes
>>> other
>>> >hosts with your list that your not suppose to deny, for example
>>> 200.0.2.16
>>> >would also be denied using your list but the question does not ask
>>> for that.
>>> >
>>> >Regards
>>> >
>>> >Lee.
>>> >
>>> >
>>> >
>>> >-----Original Message-----
>>> > From: Leigh Harrison [mailto:ccileigh@gmail.com]
>>> >Sent: 06 October 2005 14:49
>>> >To: ccielab@groupstudy.com
>>> >Subject: Double Check access-list
>>> >
>>> >Hey there,
>>> >
>>> >Could someone double check this for me? I think I've been staring
>>> at the
>>> >screen too long....
>>> >
>>> > From IEWB lab vol 1 17 Q.10
>>> >
>>> >Use the minumum lines necessary to deny these hosts:-
>>> >
>>> >200.0.1.2
>>> >200.0.3.2
>>> >200.0.3.10
>>> >200.0.1.18
>>> >200.0.3.26
>>> >200.0.1.10
>>> >200.0.3.18
>>> >200.0.1.26
>>> >
>>> >I worked it out like this:-
>>> >
>>> >128 64 32 16 8 4 2 1 #
>>> >0 0 0 0 0 0 0 1 1
>>> >0 0 0 0 0 0 1 1 3
>>> >
>>> >0 0 0 0 0 0 1 0 2
>>> >0 0 0 0 1 0 1 0 10
>>> >0 0 0 1 0 0 1 0 18
>>> >0 0 0 1 1 0 1 0 26
>>> >
>>> > From that, in the third octet, the only bit that cnages is 2 and both
>>> >variables are present. In the fourth octet, the only bits that
>>> change are
>>> >the 16 and 8 bits and all 4 variables are present.
>>> >
>>> >So I came up with :-
>>> >access-list 1 deny 200.0.1.2 0.0.2.24
>>> >access-list 1 permit any
>>> >
>>> >However, the official answer is:-
>>> >access-list 1 deny 200.0.1.2 0.0.2.8
>>> >access-list 1 deny 200.0.1.18 0.0.2.0
>>> >access-list 1 deny 200.0.1.26 0.0.2.0
>>> >access-list 1 permit any
>>> >
>>> >Am I missing something ?!?
>>> >
>>> >Time for a brew.....
>>> >LH
>>> >
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>>>
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>>
>>
>>
>>
>>
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