From: san (san.study@gmail.com)
Date: Wed Jun 22 2005 - 13:50:40 GMT-3
http://www.cisco.com/warp/public/103/19.html#var
copy paste from above url...
Let us look at an example. In the network diagram, there are three
ways to get to Network X:
*
E-B-A with a metric of 30
*
E-C-A with a metric of 20
*
E-D-A with a metric of 45
Router E chooses the second path above, E-C-A with a metric of 20,
because 20 is better than 30 and 45. To instruct EIGRP to select the
path E-B-A as well, configure variance with a multiplier of 2:
router eigrp 1
network x.x.x.x
variance 2
This increases the minimum metric to 40 (2 * 20 = 40). EIGRP includes
all routes that have a metric less than 40 and satisfy the feasibility
condition.
http://www.cisco.com/warp/public/103/19.html#var
/SAN
On 6/22/05, Jacky Murphy <ccie@maitruongxua.com> wrote:
> hi all,
>
> from source router to destination router have 4 path, configure EIGRP
> routing
>
> path A: MetricA < mixMetric * variance
> path B: MetricB = mixMetric * variance
> path C: MetricC < mixMetric * variance
> path D: MetricD < mixMetric * variance
>
> (MetricD = minMetric)
>
> in this case, MetricB=MinMetric*variance
>
> Question: Router will load balancing 4 paths (A,B,C,D) or 3 paths (A,C,D)?
> router choise the paths with metric lower than or equal mixMetric *
> variance?
>
> thank group,
> Jacky
>
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