RE: Frame relay traffic shaping ?

From: Gajewski Mariusz (Mariusz.Gajewski@telekomunikacja.pl)
Date: Tue Apr 12 2005 - 09:31:52 GMT-3


Hi guys,

Do you interpret 16kbps as 16000 bps or 16384 bps?
Should it be one of the first questions to proctor or are there any
practices used ?

Cheers,
Mariusz

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Scott Morris
Sent: Tuesday, April 12, 2005 2:04 PM
To: 'Lee Donald'; 'simon hart'; ccielab@groupstudy.com
Subject: RE: Frame relay traffic shaping ?

Note that it is 125 milliseconds, so you have to do a little calculation
there to convert your units properly. :)

Easy enough: 16k is bits per second. 125 ms is 1/8 of a second. So just
divide by 8. And that's how you get 2000 bits per timeslice from the other
two measurements in equal units.

Sometimes you'll find docs referencing in milliseconds, which makes the
conversion seem that much more complex. It's really the same but
mathematically you need to match up properly!

HTH,

Scott

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Lee
Donald
Sent: Tuesday, April 12, 2005 3:49 AM
To: simon hart; Lee Donald; ccielab@groupstudy.com
Subject: RE: Frame relay traffic shaping ?

Simon,

160000 ( 16k) divided by 125 = 1280 ? How do you get 2000 ?

Regards

Lee.

-----Original Message-----
From: simon hart [mailto:simon.hart@btinternet.com]
Sent: 11 April 2005 21:53
To: Lee Donald; ccielab@groupstudy.com
Subject: RE: Frame relay traffic shaping ?

Hi Lee,

I guess from you question you know how to determine bc, then be is a fairly
simple step. However you need to know what the Tc is for the shaped rate.
This could be explicitly defined or you maybe asked to use the default
value. If asked to use the default value then apply a map-class to the frame
port with just the cir configured and enable traffic shaping.

Then go to show traffic shaping, you will now see what the Tc value is. For
a cir of 32k you should find that this defaults to 125ms.

Therefore bc = cir*tc = 4000 bits

Now you wish to add a burst up to 48k

48k burst minus 32k cir = 16k

Therefore be = 16k/125ms = 2000

Your be value is 2000 and your bc value is 4000

HTH

Simon

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of Lee
Donald
Sent: 11 April 2005 21:28
To: ccielab@groupstudy.com
Subject: Frame relay traffic shaping ?

Hi,
Can anyone give me some pointers on frame-relay traffic shaping.
Specifically cir, bc, be.

I know roughly the cir and bc values when asked to configure parameters but
it is calculating the be that I can't get my head around.

For instance, I have a pvc that has a cir of 32k, the router is allowed to
burst up to 75% of the AR 64k. I know that is 48k but what should the "be"
value be and how do I work it out?

Thanks in advance.

Regards

Lee.



This archive was generated by hypermail 2.1.4 : Tue May 03 2005 - 07:54:56 GMT-3