From: Richard Dumoulin (richard.dumoulin@vanco.es)
Date: Mon Aug 16 2004 - 08:18:11 GMT-3
(512000 bites/second) * (10 ms) / (8 bits/byte) = 640 bytes
--Richard
-----Original Message-----
From: marc van hoof [mailto:mvh@marcvanhoof.com]
Sent: lunes, 16 de agosto de 2004 12:50
To: ccielab@groupstudy.com
Subject: IE Lab 13 Task 9.5
Anyone with this workbook know why they came up with the value of 640 for
frame-relay fragmentation ?
The task is basically a QoS task to ensure that the serialization delay of
any packet is never more than 10ms.
CIR is 512000
Any ideas ?
Thanks,
-marc.
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