Re: Quiz Question of the Day 20040502

From: alsontra@hotmail.com
Date: Mon May 03 2004 - 01:22:15 GMT-3


Yeah, my masking kunk-fu is very poor today, always- First guess was
completely wild, here's my final answer Regis....

10.0.0.0 0.129.129.0
10.0.0.0 0.65.65.0
10.0.0.0 0.33.33.0
10.0.0.0 0.17.17.0
10.0.0.0 0.9.9.0
10.0.0.0 0.5.5.0
10.0.0.0 0.3.3.0
10.1.1.0 0.0.0.0

Overlap is four nets- not sure how far is can go?

Example of my thinking-

10.128.1.0 00001010.00100000.00000010.00000000
10.1.128.0 00001010.00000001.01000000.00000000

10.0.0.0 - 00000101.00000000.00000000.00000000 AND
0.129.129.0 - 00000000.01000010.01000010.00000000 XOR

********************************************************

10.1.64.0 00000101.00000001.00100000.00000000
10.64.1.0 00000101.00100000.00000010.00000000

10.0.0.0 00000101.00000000.00000000.00000000 AND
0.65.65.0 00000000.00100001.00100010.00000000 XOR

Alsontra

----- Original Message -----
From: "Kenneth Wygand" <KWygand@customonline.com>
To: <alsontra@hotmail.com>
Cc: <ccielab@groupstudy.com>
Sent: Sunday, May 02, 2004 5:08 PM
Subject: RE: Quiz Question of the Day 20040502

> Alsontra,
>
> Unfortunately not. If you actually map out the "don't care" bits in your
masks, your first mask is "00000000.00000000.01111111.11111111". If we
don't count the last octet (because these are host bits due to the fact that
I said the networks were /24's), you have 7 "don't care" bits for your
network portion. 2^7 is 128, so you are actually matching 128 networks with
your first statement, much more than my question allowed. Likewise, your
second statement includes 14 "don't care" bits, totaling 16384 networks
(2^14).
>
> Keep thinking... and think about how the "don't care" bits work. It might
help to actual map out the networks I mentioned in binary...
>
> Good luck!
> Ken
>
> -----Original Message-----
> From: alsontra@hotmail.com [mailto:alsontra@hotmail.com]
> Sent: Sun 5/2/2004 9:50 PM
> To: Kenneth Wygand
> Cc:
> Subject: Re: Quiz Question of the Day 20040502
>
>
>
> Sorry about that. I mean..
>
> 10.1.0.0 0.0.254.255
> 10.0.1.0 0.254.254.255
>
> Thnaks- Here for lucky guesses...????
>
>
> Alsontra
>
> ----- Original Message -----
> From: "Kenneth Wygand" <KWygand@customonline.com>
> To: <ccielab@groupstudy.com>
> Sent: Sunday, May 02, 2004 4:36 PM
> Subject: Quiz Question of the Day 20040502
>
>
> > Write an access list (ACL 10) using the _fewest_ number of lines that
> denies _all_ of the following networks _without_ oversummarization and
> permits all other networks.
> >
> > 10.1.1.0 /24
> > 10.1.2.0 /24
> > 10.1.4.0 /24
> > 10.1.8.0 /24
> > 10.1.16.0 /24
> > 10.1.32.0 /24
> > 10.1.64.0 /24
> > 10.1.128.0 /24
> > 10.1.1.0 /24
> > 10.2.1.0 /24
> > 10.4.1.0 /24
> > 10.8.1.0 /24
> > 10.16.1.0 /24
> > 10.32.1.0 /24
> > 10.64.1.0 /24
> > 10.128.1.0 /24
> >
> > If you really understand how access lists work, this one should be
easy...
> :)
> >
> > Ken
> >
> > _______________________________________________________________________
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