From: Ahmed Mustafa (ahmed.mustafa@sbcglobal.net)
Date: Mon Apr 05 2004 - 16:56:16 GMT-3
How do get the 14.0.0.0
----- Original Message -----
From: "Cristian Henry H" <chenry@reuna.cl>
To: "Ahmed Mustafa" <ahmed.mustafa@sbcglobal.net>
Cc: <ccielab@groupstudy.com>
Sent: Monday, April 05, 2004 6:26 AM
Subject: Re: RP to Group Mapping
> In my opinion, the correct answer would be the following
>
> R3:
>
> !
> ip pim send-rp-announce loop0 scope 5 group-list 1
> ip pim sen-rp-discovery loop0 scope 5
> !
> access-list 1 permit 224.0.0.0 14.255.255.255 for R1
> !
> access-list 1 permit 225.0.0.0 14.255.255.255 for R2
> !
>
>
> Ahmed Mustafa ha escrito:
> >
> > If I want to configure RP to Group mapping in such a fashion that
> >
> > R3 should be a mapping agent for all multicast group for R1 with even
number
> > first octet, and
> > R3 should be a mapping agent for all multicast group for R2 with odd
number
> > second octed.
> >
> > The easiest way I could do is
> >
> > access-list 1 permit 0.0.0.0 254.255.255.255 for R1
> > access-list 2 permit 1.0.0.0 254.255.255.255 for R2
> >
> > but I want to be more granular then I can configure such as
> >
> > access-list 1 permit 224.0.0.0 7.255.255.255 for R1
> > access-list 2 permit 225.0.0.0 7.255.255255 for R2
> >
> > Can someone confirm if the 2nd option will work. I worked out in binary
it
> > looked fine.
> >
> > Regards,
> >
> > Ahmed
> >
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> --
> Cristian E. Henry
> REUNA
>
> E-mail: chenry@reuna.cl
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