RE: BGP aggregate quiz

From: Michael Snyder (msnyder@revolutioncomputer.com)
Date: Sun Feb 22 2004 - 00:28:46 GMT-3


You`re right, I've been making mistakes all day.

I was thinking 192.168.x.x was the boundary.

Did you figure out the answer to your problem?

-----Original Message-----
From: Alec [mailto:clapun@graduate.hku.hk]
Sent: Saturday, February 21, 2004 9:20 PM
To: Michael Snyder
Subject: Re: BGP aggregate quiz

isn't that class C starts with 192.X.X.X in which the first 3 bit should
be
110 ??
----- Original Message -----
From: "Michael Snyder" <msnyder@revolutioncomputer.com>
To: "'Alec'" <clapun@graduate.hku.hk>
Sent: Sunday, February 22, 2004 3:11 AM
Subject: RE: BGP aggregate quiz

> What's the upper range of class b?
>
>
>
> -----Original Message-----
> From: Alec [mailto:clapun@graduate.hku.hk]
> Sent: Saturday, February 21, 2004 12:51 PM
> To: Michael Snyder
> Subject: Re: BGP aggregate quiz
>
> Why 192.68.0.0 is not class C ???
>
> ----- Original Message -----
> From: "Michael Snyder" <msnyder@revolutioncomputer.com>
> To: <patrick.basso>
> Cc: "'Alec'" <clapun@graduate.hku.hk>
> Sent: Sunday, February 22, 2004 2:30 AM
> Subject: RE: BGP aggregate quiz
>
>
> > Oh, it's a trick question.
> >
> > 192.68.0.0 isn't class C. I was right the first time.
> >
> > -----Original Message-----
> > From: Alec [mailto:clapun@graduate.hku.hk]
> > Sent: Saturday, February 21, 2004 12:17 PM
> > To: Michael Snyder; ccielab@groupstudy.com
> > Subject: Re: BGP aggregate quiz
> >
> > Michael,
> >
> > Could u explain why prefix list can be solved ? BTW, where does the
> > prefix-list apply ? Still can't think of how does it relate to
> building
> > the
> > BGP entry in R2.
> >
> >
> > ----- Original Message -----
> > From: "Michael Snyder" <msnyder@revolutioncomputer.com>
> > To: <ccielab@groupstudy.com>
> > Cc: "'Alec'" <clapun@graduate.hku.hk>
> > Sent: Sunday, February 22, 2004 2:10 AM
> > Subject: RE: BGP aggregate quiz
> >
> >
> > > Prefix lists
> > >
> > > Something like this.
> > >
> > >
> > > ip prefix-list one seq 5 deny 192.68.0.0/16
> > > ip prefix-list one seq 10 permit 0.0.0.0/0 le 32
> > >
> > > ip prefix-list two seq 5 deny 192.68.0.0/16 ge 24 le 24
> > > ip prefix-list two seq 10 permit 0.0.0.0/0 le 32
> > >
> > > -----Original Message-----
> > > From: Alec [mailto:clapun@graduate.hku.hk]
> > > Sent: Saturday, February 21, 2004 12:03 PM
> > > To: ccielab@groupstudy.com
> > > Subject: BGP aggregate quiz
> > >
> > > Hi group,
> > >
> > > Really stuck by this BGP quiz. Anyone can shed some light ?
> Assuming
> > > two
> > > prefixes 192.68.1.0/24 and 192.68.2.0/24 are coming from the AS
and
> R1
> > > is
> > > doing an aggregate. The trickiest part is how to make build an
> entry
> > > 192.68.0.0 on R2's BGP table (note that there is no slash subnet
> > mask!!)
> > >
> > > AS ----- R1 ------ R2
> > >
> > > R1 BGP Table after aggregate
> > > *> 192.68.0.0/16
> > > *> 192.68.1.0
> > > *> 192.68.2.0
> > >
> > > R2 BGP Table which is goal to this senario.
> > > *> 192.68.0.0
> > >
> > > R1'router must advertise by 192.68.0.0 except /16'mark
> > > Don't see "/16" word in R2 and it must see "192.68.0.0" only.
> > > Don't see "S" suppress mark in R1.
> > > Don't use summary-only command by R1.
> > >
> > >
> >
>



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