From: Paul Chen (cpjchen@starhub.net.sg)
Date: Sat Jan 24 2004 - 23:29:05 GMT-3
Hi All,
Given the same metric values how does RIP decide which path to choose to a
destination network ?
I know that equal cost load balancing takes place but in this scenario , one
path is chosen over the other :
R3 R2
\ /
R5
R 141.37.106.0/24 [120/1] via 141.37.25.2, 00:00:03, Serial0
[120/1] via 141.37.35.3, 00:00:03, Serial1
R 141.37.101.0/24 [120/1] via 141.37.25.2, 00:00:03, Serial0
[120/1] via 141.37.35.3, 00:00:03, Serial1
R5#
R5#sh ip ro 141.37.101.0
Routing entry for 141.37.101.0/24
Known via "rip", distance 120, metric 1
Redistributing via rip
Last update from 141.37.25.2 on Serial0, 00:00:11 ago
Routing Descriptor Blocks:
* 141.37.25.2, from 141.37.25.2, 00:00:11 ago, via Serial0
<-------------------- This path to R2 is chosen over R3
Route metric is 1, traffic share count is 1
141.37.35.3, from 141.37.35.3, 00:00:16 ago, via Serial1
Route metric is 1, traffic share count is 1
R2 is chosen over R3 even though the metric values are the same ?
Any help appreciated.
Thanks.
Paul
This archive was generated by hypermail 2.1.4 : Mon Feb 02 2004 - 09:07:50 GMT-3