From: kasturi cisco (kasturi_cisco@hotmail.com)
Date: Tue Oct 21 2003 - 12:04:40 GMT-3
Ozgur,
The way it works is proportional to the metrics. so if ur 2 routes in
table have a metric in ratio of 3:2 meaning the better path gets 3
packets and the other path will get 2..it will send traffic proportional
to this (def : load-balanced)
Divide the (worse path metric/best path metric = X) Round off X (if
needed) to get variance ONLY and based on this u will able to get the
other route into table if it has met the Feasibilty condition. See Doyle
Vol1 for a good explanation.
http://www.cisco.com/en/US/tech/tk365/tk207/technologies_tech_note09186a008009437d.shtml#topic1
In this document they have shown how it works. My understanding is that
For path E-C-A: 30/20 = 3/2 = 1 should be actually 1.5 rounded up to 2.
So to include the link into routing table use this number for a variance
of 2. I think the "2" by itself wont help in deciding any load proportion
and load will be distributed accroding to the link metric.So 3:2 would be
the xpected behaviour. HTH.
Open to comments.
Good Luck,
Kasturi.
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