From: kasturi cisco (kasturi_cisco@hotmail.com)
Date: Sat Oct 18 2003 - 11:16:21 GMT-3
Hunt,
Looks right to me (except a small typo varience 6 ..should be variance
6). The other thing which you should possible note (may be u are aware
of) is
In this case u did not have much problem as u had both the routes in ur
EIGRP table. But lets us say bcoz of the Feasibilty criteria not being
met the second route is NOT in the table itself and u want to include it
for load balancing.
In such cases try to disconnect the better path link and connect the
worse path link. Get the metric from both.
then worse metric/better metric= X . round it off the get the
variance.Connect the better path and set variance to include the path
into EIGRP topology. The do the load balance as you have done. U could
extend the load balancing using load-balance min or balanced
(default..what u have)
http://www.cisco.com/en/US/tech/tk365/tk207/technologies_tech_note09186a008009437d.shtml#topic1
Thanks for ur post ....that i also revisited this topic and re-read.
Good Luck,
Kasturi.
>From: Hunt Lee >Reply-To: Hunt Lee >To: ccielab@groupstudy.com >Subject:
Am I correct? >Date: Fri, 17 Oct 2003 09:58:08 +1000 > >Hey Group, > >Can
someone please confirm that my method is correct for EIGRP load
balancing? > >R5 ----- R6 ---- 142.1.6.0/24 > >E.g. At R5's
EIGRPtopology's table > >P 142.1.6.0/24, 1 successors, FD is 409600 >via
142.1.56.6 (409600/128256), Ethernet0 >via 142.1.65.6 (2297856/128256),
Serial1 > >Now, if I want to do equal cost load balance between the 2
links > >2297856 - 409600 = 1888256 > >Then on R5: >offset-list 0 in
1888256 Ethernet0 > >Correct? > >But if I want to do un-equal cost load
balancing, say if I want to send 6 packets to Ethernet 0, then send 1
packet to Serial 1. > >409600 * 6 = 2457600 > >2457600 - 2297856 = 159744
> >Then on R5: >offset-list 0 in 159744 Serial1 >varience 6 > >Am I
correct? > >Thank you so much!!! >Hunt >
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