From: Ken.Farrington@barclayscapital.com
Date: Fri Oct 03 2003 - 11:55:58 GMT-3
Many thx for this guys
"By default, Open Shortest Path First (OSPF) supports four equal cost paths
to a destination. In this scenario Router B is configured with maximum-paths
equal to one. Hence Router B will choose only one path amongst the possible
equal paths based on which one it received first. Router B starts by
selecting Serial 2 as the single path to the 194.168.20.0 network. "
As per the statment above, we can assume that EIGRP is the same and any
other routing protocol.
Correct?
-----Original Message-----
From: Micah Byers [mailto:mbyers@gramtel.net]
Sent: 03 October 2003 15:31
To: Ken.Farrington@barclayscapital.com; ccielab@groupstudy.com
Subject: RE: Maximum-Paths 4 (Router has 6 paths - what 4 paths does the
routi ng table choose)
Ken,
Good question. The paths that will be selected are those which are
received first.
http://www.cisco.com/en/US/tech/tk827/tk831/technologies_tech_note09186a0080
094806.shtml
Micah J. Byers- CCIE #12079
Senior Network Engineer
Hypervine
mbyers@hypervine.net
P: 574-472-4726
F: 574-472-0904
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Ken.Farrington@barclayscapital.com
Sent: Friday, October 03, 2003 3:51 AM
To: ccielab@groupstudy.com
Work question here. - sorry if not appropriate to the forum.
If you have 6 equal cost paths to a destination, and you have in IGRP/EIGRP
or OSPF the default max-paths set to 4.
Which 4 paths does the routing table pick to be entered into the routing
table.
Is it based on neighbour IP?
Many thx
Ken
________________________________________________________________
Ken Farrington
Global Networks, Barclays Capital, 5 The North Colonnade, Canary
Wharf, London, E14 EBB
* Tel : 020 7773 3550
* Mob : 07768-866655
* ken.farrington@barcap.com
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