RE:

From: Jonathan V Hays (jhays@jtan.com)
Date: Sun Jul 13 2003 - 12:32:54 GMT-3


It will *not* meet the requirements, which by the way are very vaguely
stated. What kind of weight? QoS? BGP?

[And PLEASE put something meaningful in your subject header, okay?]

As we know, the basic formula for matching even routes is 0 for the
subnet and 254 for the inverse mask.
To match all 172.16.x.0 even routes, where x is 1,2,3,4,5 ... 255 do
this:

permit 172.16.0.0 0.0.254.0

To match odd routes:

permit 172.16.1.0 0.0.254.0

Even numbers: 0000, 0010, 0100, 0110, 1000, etc. <- all end in 0

Odd numbers: 0001, 0011, 0101, 0111, 1001, etc. <- all end in 1

HTH

> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On
> Behalf Of Emad
> Sent: Sunday, July 13, 2003 10:47 AM
> To: 'ccie'; ccielab@groupstudy.com
> Subject: RE:
>
>
> Hi,
> Can u plz define in more descriptive way how come will this answer
> suffice the requirements?
>
> Regards
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On
> Behalf Of
> ccie
> Sent: Sunday, July 13, 2003 12:39 PM
> To: ccielab@groupstudy.com
> Subject: RE:
>
> Hi,
>
> You can use .*
>
> bye
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> George Gittins
> Sent: Sunday, July 13, 2003 3:53 AM
> To: ccielab@groupstudy.com
> Subject:
>
>
> im stuck with this question regarding regular expression, how would i
> apply
> a regular expresion to match all even routes and give it a
> higher weight
>
>
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