RE: Regular expression

From: Jung, Jin (jin.jung@lmco.com)
Date: Wed Jun 18 2003 - 16:22:27 GMT-3


Hi Chris,,
Nice try but that will allow all the routes that are originated from 100.

The question asks "AS 100 and directly connected only"..which is one hop
from 100 only.

So I think ^100_[0-9]*$ should work, --- I think.

This will only allow originated AS and directly connected ASs only,

Jin jung....

-----Original Message-----
From: Chris Home [mailto:clarson52@comcast.net]
Sent: Wednesday, June 18, 2003 2:36 PM
To: nsevasti@cisco.com; ccielab@groupstudy.com
Subject: Re: Regular expression

Just a guess. I would be looking for the right answer too but...

route-map something in

neigh x.x.x.x route-map something in

route-map something permit 10
match add as-path 2

ip as-path access-list 2 permit ^100_

I would think this would allow anything in that originated from 100 and
include anything it is dorectly connected too.

----- Original Message -----
From: <nsevasti@cisco.com>
To: <ccielab@groupstudy.com>
Sent: Wednesday, June 18, 2003 8:57 AM
Subject: Regular expression

> Hi,
> can anyone help with a regular expression that would permit bgp to
> accept
from a neighbor(EBGP) using an ip as-path access-list just the routes that
originate in the neighbor's AS and it's DIRECTLY connected AS's?
>
> Like if the neighbor is in AS 100 and directly connected with it are
> 2000
and 30000, the expression would match
>
> 100
> 100 2000
> 100 30000
>
> and any other AS's DIRECTLY connected to 100
>
> Bye,
> Nark
>
>
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