From: SHARMA,MOHIT (HP-Germany,ex1) (mohit.sharma@hp.com)
Date: Wed Jun 18 2003 - 10:30:05 GMT-3
or use
^100 ?[0-9]*$
also take care of the bracket, it should be a [] and not ().
-----Original Message-----
From: Puranik, Deepak, NPONS [mailto:dpuranik@att.com]
Sent: Wednesday, June 18, 2003 3:14 PM
To: nsevasti@cisco.com; ccielab@groupstudy.com
Subject: RE: Regular expression
^100_(0-9)*$
Deepak Puranik
-----Original Message-----
From: nsevasti@cisco.com [mailto:nsevasti@cisco.com]
Sent: Wednesday, June 18, 2003 7:58 AM
To: ccielab@groupstudy.com
Subject: Regular expression
Hi,
can anyone help with a regular expression that would permit bgp to
accept from a neighbor(EBGP) using an ip as-path access-list just the
routes that originate in the neighbor's AS and it's DIRECTLY connected
AS's?
Like if the neighbor is in AS 100 and directly connected with it are
2000 and 30000, the expression would match
100
100 2000
100 30000
and any other AS's DIRECTLY connected to 100
Bye,
Nark
This archive was generated by hypermail 2.1.4 : Fri Jul 04 2003 - 11:11:00 GMT-3