From: Oliver Ziltener (ziltener@netcloud.ch)
Date: Mon May 19 2003 - 12:22:07 GMT-3
Hello
why you use this list 101 for dlsw+?
I think 1981-1983 are used only with priorisation and for the port 2067 I
dont know...
Oliver
-----Ursprungliche Nachricht-----
Von: Jeongwoo Park [mailto:jpark@wams.com]
Gesendet: Montag, 19. Mai 2003 16:17
An: 'Tom Young'; ccielab@groupstudy.com
Betreff: RE: the queue-list
Tom,
Byte count is done in byte, not bit.
The default 10 % was measured in byte of 1500.
However, my answer would be as following;
access-list 101 permit tcp any any eq 2065
access-list 101 permit tcp any eq 2065 any
access-list 101 permit tcp any any eq 2067
access-list 101 permit tcp any any eq 1981
access-list 101 permit tcp any any eq 1982
access-list 101 permit tcp any any eq 1983
queue-list 1 protocol ip 0 list 101
queue-list 1 protocol ip 1
queue-list 1 protocol ipx 2
queue-list 1 default 3
queue-list 1 queue 0 byte-count 7500
queue-list 1 queue 1 byte-count 3750
queue-list 1 queue 2 byte-count 2250
Other ideas?
Which one would you vote for?
JP
-----Original Message-----
From: Tom Young [mailto:gitsyoung@yahoo.co.jp]
Sent: Monday, May 19, 2003 2:06 AM
To: ccielab@groupstudy.com
Subject: the queue-list
Hi, group
I really confused, I had asked this question for somebody
but hadn't got answer, it is that want to pay the half
bandwidth of serial port for dlsw, and 25% for ip , 15%
for IPX and 10% for the default. That is the answer as
below.
queue-list 1 protocol dlsw 0
queue-list 1 protocol ip 1
queue-list 1 protocol ipx 2
queue-list 1 default 3
queue-list 1 queue 0 byte-count 7500
queue-list 1 queue 1 byte-count 3750
queue-list 1 queue 2 byte-count 2250
But I think the bandwidth of serial port is 1.5M , that
1500000bps, is 150000Bps, so, 50% of serial port should be
75000 not the 7500. So I think the answer should be 75000,
37500 , 22500, right?
Hope someone could give me a correct answer, thanks alot .
This archive was generated by hypermail 2.1.4 : Mon Jun 02 2003 - 15:13:45 GMT-3