From: midaskim (janggulove@hanmail.net)
Date: Mon Apr 21 2003 - 11:36:25 GMT-3
Kashif Ali
you misunderstood "5%" Park mentioned.
He commented 5% means randomly drop packet percentage.
random-detect precedence 5 40 60 20
In here, 20 means "randomly drop 1packet per 20 packets" if exceed 60
So. 1/20 means 5%
---------[ 9^@: 8^@O 3;?k ]----------
A&8q : RE: random-detect precedence 5 40 60 20-Confusion
3/B% : Mon, 21 Apr 2003 06:15:18 -0700 (PDT)
:83=@L : Kash <kash2331@yahoo.com>
9^4B@L : Daniel Cisco Group Study <danielcgs@imc.net.au>, Jeongwoo
Park <jpark@wams.com>
GT229^4B@L : ccielab@groupstudy.com
Hi
I might be wrong on this but can someone correct me
the 5 on the command means the precedence right, not
5%.
The way I interpret this is that on all packets that
have precedence value of 5 and if they remain in the
40-60 range than its ok if it goes higher than 60 than
randonmly 1 packet out of 20 will be dropped(having
precedence 5)
Kashif Ali
--- Daniel Cisco Group Study
wrote:
> My understanding agrees...
>
> Anyone else?
>
> Daniel
>
>
> -----Original Message-----
> From: Jeongwoo Park [mailto:jpark@wams.com]
> Sent: Friday, 18 April 2003 11:50
> To: 'ccielab@groupstudy.com'
> Subject: random-detect precedence 5 40 60 20
>
>
> Hi all,
> I am trying to interpret the last parameter of this
> command.
> At the router it is showing as following;
>
> r4(config-if)#random-detect precedence 5 40 60 ?
> <1-65536> mark probability denominator
>
>
> r4(config-if)#random-detect precedence 5 40 60 20
>
> Does this mean that if the number of packets exceed
> the range of 40 to 60,
> the router would randomly drop the packet at the
> rate of 5%, a packet for
> every 20 packets?
> Did I interpret it correctly?
>
> Thanks a lot.
>
> JP
>
>
>
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