From: Danny Andaluz (dannyandaluz@comcast.net)
Date: Fri Apr 11 2003 - 23:10:21 GMT-3
What I have is the following:
Route Reflector
| | |
| | |
RRc RRc non-client
IBGP assumes a full mesh. If that non-client does not have an IBGP
connection to either of those RR-clients and only has an IBGP connection to
the RR, then how, if the RR does not have the non-client configured a
RR-client, does the non-client get the route being advertised to the RR from
one of the clients? IBGP assumes a full mesh. The RR assumes that the
non-client has an IBGP connection the clients, so he would not send the
route (loop avoidance). If the route reflector reflects the routes to the
non-client as well, what's the point of having RR's. I'm probably still
missing something.
----- Original Message -----
From: "OhioHondo" <ohiohondo@columbus.rr.com>
To: "Danny Andaluz" <dannyandaluz@comcast.net>; <ccielab@groupstudy.com>
Sent: Friday, April 11, 2003 8:30 PM
Subject: RE: BGP question
> Danny
>
> When you use route reflectors, all RR's and non-clients have to be in a
full
> mesh. The RR clients "hang" off of the RR's. In your scenario you have a
RR
> with 2 RR clients. The RR is also connected to a non-client (a BGP router
in
> the same AS that is another RR or just has IBGP sessions with
non-clients).
>
> Since you only have 2 non-clients, you have a full mesh.
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> Danny Andaluz
> Sent: Friday, April 11, 2003 4:05 PM
> To: ccielab@groupstudy.com
> Subject: BGP question
>
>
> I have a question about non-clients in a route-reflector topology.
> Assuming all routers are in the same AS, you have a hub and spoke topology
> where the RR has three peerings with three different routers. Only two of
> those neighbors are configured as route-reflector-clients. In Doyle's
> routing TCPIP V. 2 pg. 127, it says that if a RR learns a route from a
> RR-client that route will be sent to the other RR-client as well as the
> non-client. I am under the impression that a non-client is simply a
> neighbor that is not configured as a RR-client in the RR. If this
> non-client was in a different AS, I can see this happening because that is
> EBGP, but IBGP assumes a full mesh, so how could the RR send this route to
> the non-client? Of course, I'm going on the assumption that a non-client
is
> what I described previously. So I guess my question really is, what is a
> non-client?
> TIA,
> Danny
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