From: Scott M. Livingston (scottl@sprinthosting.net)
Date: Tue Apr 08 2003 - 13:13:50 GMT-3
Sorry about my second example. My typo was just pointed out to me. It
should have been.
Bc = CIR * .125
8000 = 64000 * .125
thanks,
scott
-----Original Message-----
From: Scott M. Livingston [mailto:scottl@sprinthosting.net]
Sent: Monday, April 07, 2003 9:16 PM
To: 'rich@myhomemail.net'; 'wsqccie@hotnail.com'; 'Rick';
'ccielab@groupstudy.com'
Subject: RE: QOS question on Bc with CAR
Richard,
I have read it over once and it looks good to me, (remember I am no QOS
guru), but so that nobody is confused..... the original topic was
related to CAR not FRTS. But hey why not wrap some FRTS up in this one
too; it's all a booger to me. eheheheh. Thanks for taking the time here
man!!
So for FRTS Bc =
Bc = CIR/8
8000 = 64000/8
-OR-
Bc = CIR * .125
8000 = 64000/8
thank you,
scott
-----Original Message-----
From: Richard Davidson [mailto:rich@myhomemail.net]
Sent: Monday, April 07, 2003 5:48 PM
To: wsqccie@hotnail.com; Rick; ccielab@groupstudy.com; Scott M.
Livingston
Subject: Re: QOS question on Bc with CAR
I just figured this out but I think I have it down.
Any corrections are welcome.
An interface has an access rate. That access rate may
be 128kbps. That access rate is divided up in to
transmission over the course of time. Think of the
total of 1 second to be T. Draw this out. Vertically
is the bandwidth and horizontally is time. Over the
course of time, you want to transfer data. The T in
this case time, represents 1 second. This one second
is broken in what you know as Tc. Tc is an increment
of the T which is in msec. 1 second / 8 = .125. This
is what is usually used as the Tc (.125). If you are
using Voice, the T (1 second) is recommended to be
broken into 10 time slots. 1 second / 10 = .1.
Well if my Tc is .125 and (Tc=Bc/CIR or Bc=CIR*Tc)
then Bc=CIR*.125. To find the Bc, we need to know
what the CIR is. If the CIR is 64k then over the
course of time I should average out to 64k. If
Bc=64000*.125 then my BC is 8000. Remember, we have
broken this T ( 1 second) into 8 segments. So over
the course of, 1 second we will transfer The amount of
traffic transmitted in Tc * 8. Well already said the
Bc is 8000 so (8000*8) = 64000, Also the CIR.
Rich
--- "wsqccie@hotnail.com" <wsqccie@hotmail.com> wrote:
> maxir=cir(1+be/bc)
> bc=cie*tc , normal tc=125ms
> ----- Original Message -----
> From: "Rick" <ccie_2003@hotmail.com>
> To: <ccielab@groupstudy.com>; "Scott M. Livingston"
> <scottl@sprinthosting.net>
> Sent: Monday, April 07, 2003 10:37 AM
> Subject: Re: QOS question on Bc with CAR
>
>
> > This what I found too in the cisco press Qos book,
> but it never matches up
> > with any of their answers..
> >
> > Thanks,
> > Rick
> > ----- Original Message -----
> > From: "Scott M. Livingston"
> <scottl@sprinthosting.net>
> > To: "'Rick'" <ccie_2003@hotmail.com>;
> <ccielab@groupstudy.com>
> > Sent: Sunday, April 06, 2003 10:25 PM
> > Subject: RE: QOS question on Bc with CAR
> >
> >
> > > W/ CAR I use:
> > >
> > > Bc = configured rate / 8 * 1.5
> > > Be = Bc * 2
> > >
> > > thanks,
> > > scott
> > >
> > > -----Original Message-----
> > > From: nobody@groupstudy.com
> [mailto:nobody@groupstudy.com] On Behalf Of
> > > Rick
> > > Sent: Sunday, April 06, 2003 8:22 PM
> > > To: ccielab@groupstudy.com
> > > Subject: QOS question on Bc with CAR
> > >
> > > Can soneone please explain a simple way to
> figure out the Bc with CAR. I
> > > have
> > > been simply dividing the access rate by 8. I
> know this can't be right
> > > because
> > > my numbers never match the book. Any help would
> be greatly appreciated.
> > >
> > > Thanks,
> > > Rick
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