From: Mahmud, Yasser (YMahmud@Solutions.UK.ATT.com)
Date: Sun Mar 30 2003 - 08:06:33 GMT-3
Your solution no. 2 is wrong as the wildcard mask has 0 for the bit with
weight of 8 so you will be missing the networks that need weight 8 e.g
172.16.40.0
Yasser
-----Original Message-----
From: Voss, David [mailto:dvoss@heidrick.com]
Sent: Sunday, March 30, 2003 3:13 AM
To: 'ccielab@groupstudy.com'
Subject: ACL Test
Allow from 172.16.32.0 to 172.16.247.255 in least amount of lines.
Solution #1:
access-list 1 deny 172.16.0.0 0.0.31.255
access-list 1 deny 172.16.248.0 0.0.7.255
access-list 1 permit 172.16.0.0 0.0.255.255
Solution #2:
access-list 1 permit 172.16.32.0 0.0.215.255
Which one would you choose?
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