RE: Traffic-shaping question

From: CCIE FUN (ccieexam2002@yahoo.com)
Date: Sat Mar 29 2003 - 14:21:27 GMT-3


Daniel
After reading a document on the cisco website.Now i
have understood how you came up with the value of
Be=2000.
It definately makes sense. I agree with your solution.

Thanks for explaining this.

--- Daniel Cisco Group Study <danielcgs@imc.net.au>
wrote:
> Firstly,
>
> In the following command:
>
> frame-relay be 16000
>
> be is specified in bits....
>
> Router(config-map-class)#frame-relay be ?
> <0-16000000> Applied to both Incoming/Outgoing
> Be, Bits
> in Incoming Be (Frame-Relay SVC only)
> out Outgoing Be
> <cr>
>
> Secondly,
>
> If you look carefully at the first 125msec time
> interval, we transmit 2000 + 6000 = 8000 bits. (Like
> you said below)
>
> That's 8000 bits in 125msec, which actually
> translates to 64000bps (for a period of 125ms).
>
> Thus, you are able to burst in the first time
> interval, all the way to 64000bps. Every time
> interval after that, we transfer only 6000 bits per
> 125ms interval - ie 48000bps.
>
> You are correct in saying that the net rate is
> 50kbps (for the entire 1 sec period). But keep in
> mind that because you have no tokens left in the
> bucket after this 1 sec period, you won't be
> bursting in the next 1 sec period.... ie you'll be
> stuck on cir of 48kbps until some point later when
> you transmit at less than this rate (and you begin
> to accumulate tokens in the bucket).
>
> Hope I haven't confused the issue. The best way to
> understand this is using the token bucket analogy
> (which I'll leave up to you or to another colleague
> to dig up a good URL for...)
>
>
> Daniel
>
>
> -----Original Message-----
> From: CCIE FUN [mailto:ccieexam2002@yahoo.com]
> Sent: Saturday, 29 March 2003 13:50
> To: Daniel Cisco Group Study; ccielab@groupstudy.com
> Subject: RE: Traffic-shaping question
>
>
> Daniel
> Be is in bits per second.
> The Be value calculated by you is correct, however
> it
> 2000Bits per time interval(125ms)
> so ultimately the Be for 1 sec(125 ms * 8) is
>
> 2000 * 8 = 16000bps.
>
> Yes you can only burst for the first time interval
> however if you use the value of 2000
> then here is what is transmitted in 1sec
>
> 2000(be)+6000(bc)=8000-1st time interval
> (125ms)
> 6000(bc)--2nd time interval(125ms)
> 6000(bc)--3nd time interval(125ms)
> 6000(bc)--4th time interval(125ms)
> 6000(bc)--5th time interval(125ms)
> 6000(bc)--6th time interval(125ms)
> 6000(bc)--7th time interval(125ms)
> 6000(bc)--8th time interval(125ms)
> so the total is 50Kbps
>
> But the port speed is 64Kbps this means we can burst
> upto 64Kbps. so how do i get to that?
>
> My understanding was that the router will send
> send the full Be amount during the first time
> interval.
> and remaining 7 time interval it will be only Bc.
>
> so adding all that i get the net result of 64000.
>
> i am getting too confused with this now.i hope my
> understanding is correct.
>
> because i have been getting varying solutions for
> this
> one.
>
>
>
>
>
> --- Daniel Cisco Group Study <danielcgs@imc.net.au>
> wrote:
> > Shouldn't be=2000 ?
> >
> > (AR - CIR) / 8
> >
> > (64000 - 48000) / 8
> >
> > You are using a 125ms time interval, and you can
> > only burst in the first one. Also, be is in bits,
> > not bps.
> >
> > Daniel
> >
> > -----Original Message-----
> > From: CCIE FUN [mailto:ccieexam2002@yahoo.com]
> > Sent: Saturday, 29 March 2003 02:54
> > To: ccielab@groupstudy.com
> > Subject: Traffic-shaping question
> >
> >
> > Hello all,
> > I have traffic-shaping question and i have also
> > mentioned the solution i used.
> >
> > please help me out to identify if it's correct and
> > what commands are useful to determine that the
> > traffic
> > shaping is going to work as configured.
> >
> > Here is the question:
> > 1.The router R5 has two PVC's going R1 and R13
> each
> >
> > has CIR of 48Kbps and burst size of 64Kbps.
> >
> > 2. The circuit from R5 to the frame-relay switch
> is
> > provisioned at a speed of 64Kbps.
> >
> > 3. If BECN's are recieved, R5 needs to throttle
> back
> >
> > back the PVC's to 32Kbps.
> >
> > 4. Using CIR, Bc and Be configure traffic-shaping
> on
> >
> > R5.
> >
> > Now here is my config for Router R5 relevant to
> > Traffic-shaping. I have not shown any frame-maps
> or
> > IP
> > information for clarity purposes.
> >
> > !
> > interface s0
> > encap fram
> > no arp fram
> > no fram inv
> > frame-relay traffic-shaping
> > frame-relay class Shape
> > !
> > map-class frame-relay Shape
> > frame-relay cir 48000
> > frame-relay bc 6000
> > frame-relay be 16000
> > frame-relay mincir 32000
> > frame-relay adaptive-shaping becn
> >
> >
> >
> > Now my question is do i need to configure R1 and
> R13
> > for shaping even if it is not mentioned in the
> > Question.
> >
> > Also is my solution correct.
> >
> >
> > Thanks for your help.
> >
> > __________________________________________________
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