From: matijevi@bellsouth.net
Date: Wed Feb 19 2003 - 16:56:15 GMT-3
Got it guys, thanks for all the feedback.
John
----- Original Message -----
From: "Ram Shummoogum" <rshummoo@ca.ibm.com>
To: <matijevi@bellsouth.net>
Cc: <ccielab@groupstudy.com>
Sent: Wednesday, February 19, 2003 2:19 PM
Subject: Re: FD with EIGRP
> Your sh int lo 0 wil probably have a bandwith of 8000000 kbit and a delay
> of 5000 microsec
>
> The formula is (10000000/8000000)=1.25
> Cisco routers do not do floating point, therefore you should round down to
> 1.
>
> Divide the delay by 10. i.e (5000/10) = 500
>
> The magic number is (500 +1) * 256 = 128256
>
>
> The second number within the parenthesis is the advertised distance and
the
> first one(FD) is equal to the AD + the metric to reach that next hop.
>
> HTH
>
> RAM
>
>
>
> matijevi@bellsouth.net@groupstudy.com on 02/19/2003 11:18:46 AM
>
> Please respond to matijevi@bellsouth.net
>
> Sent by: nobody@groupstudy.com
>
>
> To: <ccielab@groupstudy.com>
> cc:
> Subject: FD with EIGRP
>
>
> I have enabled EIGRP on 2 routers placing a loopback and ethernet
interface
> only into the process.
>
> r3#sh ip eigrp topology
> IP-EIGRP Topology Table for AS(35)/ID(172.16.103.1)
>
> Codes: P - Passive, A - Active, U - Update, Q - Query, R - Reply,
> r - reply Status, s - sia Status
>
> P 172.16.32.0/22, 1 successors, FD is 281600
> via Connected, Ethernet0/0
> P 172.16.105.0/24, 1 successors, FD is 409600
> via 172.16.35.5 (409600/128256), Ethernet0/0
> P 172.16.103.0/24, 1 successors, FD is 128256
> via Connected, Loopback0
>
>
> r5#sh ip eigrp topology
> IP-EIGRP Topology Table for AS(35)/ID(172.16.35.5)
>
> Codes: P - Passive, A - Active, U - Update, Q - Query, R - Reply,
> r - reply Status, s - sia Status
>
> P 172.16.32.0/22, 1 successors, FD is 281600
> via Connected, Ethernet0
> P 172.16.105.0/24, 1 successors, FD is 128256
> via Connected, Loopback105
> P 172.16.103.0/24, 1 successors, FD is 409600
> via 172.16.35.3 (409600/128256), Ethernet0
>
> How is the FD derived from the loopback on a local router, when that
> loopback
> is placed in EIGRP? The table shows FD is 128256. How is this number
> derived?
> Also, how is the other numbers derived? Finally I remeber reading in
> Doyle's
> book that the first number in parenthesis is the metric calculated by the
> local router to the destination, and the second number in the partenthesis
> is
> the metric advertised by the neighbor, why is it using the loopback
metric,
> as
> the advertised metric, is it because thats the lowest metric calculated by
> the
> dual algorithm?, I just want to know exactly how these numbers are
> calculated
> if I have a 10mb connection between R3 and R5?
>
>
> Sincerely,
> John
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