From: OhioHondo (ohiohondo@columbus.rr.com)
Date: Sun Feb 23 2003 - 03:58:21 GMT-3
Daniel
This is another confusing issue. Burst and excessive burst are two different
things. Excessive burst is always in the first Tc. ;)
-----Original Message-----
From: Daniel Cisco Group Study [mailto:danielcgs@imc.net.au]
Sent: Sunday, February 23, 2003 1:44 AM
To: Jerry Haverkos; Sage Vadi; ccielab@groupstudy.com
Subject: RE: FRTS: Bc & minCIR
Jerry,
The question stated a burst size of 19,200 bps. (Note - it was specified in
bps, not bits). That's why I suggested be=2400.
Daniel
-----Original Message-----
From: Jerry Haverkos [mailto:jhaverkos@columbus.rr.com]
Sent: Sunday, 23 February 2003 17:19
To: Daniel Cisco Group Study; Sage Vadi; ccielab@groupstudy.com
Subject: RE: FRTS: Bc & minCIR
Note -- the excess burst all occurs during the first Tc time period so you
do not multiply the 19200 bits per second by 125 milliseconds. Excess burst
(Be) is not allowed during the other seven Tc time periods.
The burst occurs during the first time period only. Depending on how the
question is phrased/understood Burst can be calculated as:
1) the number of bits above Bc in the first time period. In this case burst
would be Be= 19200
2) the total number of bits transmitted in the 1st Tc time period. In this
case burst would be Be-Bc or 19200-1200=1800
So in case# 1 the number of bits transmitted in the first Tc time period
would be Bc+Be or 1200+19200=20400
In case#2 the number of bits transmitted in the first Tc time period would
be Bc+Be or 1800+1200=19200
My guess would be case# 1. ;)
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
Daniel Cisco Group Study
Sent: Saturday, February 22, 2003 11:15 PM
To: Sage Vadi; ccielab@groupstudy.com
Subject: RE: FRTS: Bc & minCIR
I would have chosen the following parameters:
frame-relay cir 9600 (in bits/s)
frame-relay bc 1200 (in bits) -->( cir/8 )
frame-relay be 2400 (in bits) -->( 19200 / 8)
I have assumed a time interval of 125ms.
So, if the burst is 19600 bits per second, then be=19200 x 0.125 = 2400.
ie, the frame-relay interface would transfer at 9600 + 19200 = 28800 bits/s
in the first Tc.
Anyone second this?
Daniel
-----Original Message-----
From: Sage Vadi [mailto:sagevadi@yahoo.co.uk]
Sent: Saturday, 22 February 2003 13:09
To: ccielab@groupstudy.com
Subject: FRTS: Bc & minCIR
All,
Q) Configure your frame-relay network to have a
committed information rate of 9,600 bps and a burst
size of 19,200 bps.
So would this be correct - ?
frame-relay CIR 9600
frame-relay Bc 9600
The Bc figure is what I am concerned about. Reading
the documentation, CCO states the peak is = CIR + Be.
Therefore that would mean CIR=9600 + Be = 19200, so I
arrived @ Bc figure of 9600.
Also in the traffic-rate command it is explained that
the Be value is calculated from subracting the average
from the peak. In my case average would be 9600, minus
this from a peak of 19200 would also equal 9600.
Furthermore I have a question about minCIR - according
to CCO, "rate values greater than 2048 must be entered
with trailing zeros. For example, 2048000 and 5120000"
- what on earth does that mean? And why do you have to
do this???
Lastly if the minCIR value cannot be supported, the
call is cleared (direct quote CCO). Does this mean
that CIR by itself is not as stringent as the minCIR,
so that would mean CIR does some negotiation with the
endpoint - how does this work?
rgds,
Sage
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