From: Emre Koyuncu (emrekoyuncu@hotmail.com)
Date: Wed Feb 19 2003 - 03:56:21 GMT-3
Hi ,
Actually by using these calculations , you can get the solution for packet
count not the byte count. The correct solution must be the following way :
www traffic gets 50% =>> the value can be 5000 (it can be anything as long
as it is rational with the other values)
FTP /Telnet get 15% =>> the value can be 1500
Traffic from e0/0 gets 15% =>> the value can be 1500.
I assume the rest ,20% is going to default queue. =>> the value can be 2000
By this way after transmitting 5000 bytes of www traffic, you will begin
transmitting FTP/Telnet traffic for 1500 bytes after that you will transmit
traffic from e0/0 for 1500 bytes after that the rest of the traffic will be
transmitted for 2000 bytes the cycle goes on. In one cycle which is 10000
bytes , www traffic transmits 5000 bytes which is 50% of the total traffic,
FTP/telnet transmits 1500 bytes which is 15% of total traffic, e0/0
transmits 1500 bytes , the rest will transmit 2000 bytes.
This way is easy for calculation. And you use the queue-list byte-count
command.
But by using cannonr's calculation you have to queue-list limit command. And
this will be the calculation with the packet count.
Emre Koyuncu CCIE #10916
----- Original Message -----
From: "cannonr" <cannonr@attbi.com>
To: "CCIE FUN" <ccieexam2002@yahoo.com>; <ccielab@groupstudy.com>
Sent: Tuesday, February 18, 2003 9:00 PM
Subject: Re: Custom Queuing byte count calculation
> You question would usually include a packet size for each protocol. Here
is
> an example if you have a packet size for each.
>
> DLSW gets 25% and has a 512KB packet size
> Telnet gets 25% and has a 1500 KB packet size
> Citrix gets 50% and has a 1500 KB packet size
>
> To figure out byte count use the following formula.
>
> Divide the percentage for each protocol by packet size.... You get the
> following.
>
> DLSW 25/512 = .048848
> Telnet 25/1500 = .01666
> Citrix 50/1500 = .03333
>
> Divide the output of each by the smallest number.
>
> DLSW .048848/.01666 = 2.93
> Telnet .01666/.01666 = 1
> Citrix .03333/.01666 = 2.0006
>
> Round this number and multiply by byte count.
>
>
> DLSW 3X512 = 1536
> Telnet 1X1500 = 1500
> Citrix 2X1500 = 3000
>
>
> Now to verify that you are close to the proper percentages by adding all
> byte counts and dividing by each one.
>
> 1536+1500+3000=6036
>
> DLSW 1536/6036=.25473
> Telnet 1500/6036=.2485
> Citrix 3000/6036=.4970
>
> If you do not round up in the earlier step, you this formula will come a
> little closer to the exact numbers, but using DLSW as an example, if you
> were to multiply 2.93 X 512, you actually get 1500.16 as a byte counte.
If
> you use 1500 as your number, you will still send 3 packets before your
turn
> is up which equals 1536..... That's as close as you can get!
>
>
> HTH
>
>
>
>
> ----- Original Message -----
> From: "CCIE FUN" <ccieexam2002@yahoo.com>
> To: <ccielab@groupstudy.com>
> Sent: Tuesday, February 18, 2003 9:37 PM
> Subject: Custom Queuing byte count calculation
>
>
> > Hello Group
> > Can anybody explain the best way to calculate the
> > byte-count. i am working on a example
> > "it says that configure custome queueing on frame
> > cloud so if congestion occurs then:
> >
> > www traffic gets 50% traffic
> > FTP /Telnet get 15%
> > Traffic from e0/0 gets 15%
> > rest of the traffic shares the remaining bandwidth.
> >
> > Now how do i determine the byte-count in this case.
> > I have worked on examples which provide the
> > predetermined byte-counts, the DOC CD has a nice
> > example on that.
> > But have always stumbled upon the kind of examples i
> > explained above.
> >
> > any help would be appreciated.
> >
> > thanks
> >
> > __________________________________________________
> > Do you Yahoo!?
> > Yahoo! Shopping - Send Flowers for Valentine's Day
> > http://shopping.yahoo.com
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