From: Erick B. (erickbe@yahoo.com)
Date: Tue Dec 10 2002 - 03:39:50 GMT-3
Since the 2nd, 3rd, and 4th octects are the same the
last 3 parts of the wildcard mask will be 0's. let's
focus on the 1st octect.
Break them down into binary like below:
128 64 32 16 8 4 2 1
------------------------------------
160 1 0 1 0 0 0 0 0
161 1 0 1 0 0 0 0 1
170 1 0 1 0 1 0 0 1
Find the common bit for the networks you want to
summarize.
The 4th bit (16) is the match for 160, 161, and 170.
128 + 64 + 32 + 16 = 240 -- this is your wc mask for
summary
This will also include some other networks (162, 165,
etc). You could summarize it more but that would
include more networks besides the ones above.
--- Bobby <bobby1@ctimail3.com> wrote:
> Hi,
>
>
> In one of the pratice labs you are asked to
> summarize the following 3
> loopbacks into one single route :
>
> Loopback 1 : 160.10.10.1/24
> Loopback 2 : 161.10.10.1/24
> Loopback 3 : 170.10.10.1/24
>
> And the answer is ip summary-address eigrp 1
> 160.0.0.0 240.0.0.0
>
> Please let me know about any link or technqiue where
> I can fully understand
> the above summarization.
>
> Thanks
This archive was generated by hypermail 2.1.4 : Fri Jan 17 2003 - 17:21:42 GMT-3