From: Raj (raj.bahad@totalise.co.uk)
Date: Fri Sep 13 2002 - 19:38:28 GMT-3
Hi Group,
I'm confused over a new command i have come across for BGP. Picture this if
you will,
R5------------------------R1----------------------R2
(BGP) (BGP/ RIP) (RIP)
Essentially, R1 is running BGP and RIP. R1 also has IBGP connections to
other routers. RIP and BGP are mutually redistributed on R1.
R2 learns about BGP routes which are only attached directly to R1 (Loopback
0, Serial 1), however, all the other BGP routes which R1 has learnt from its
iBGP peering are not present in R2's routing table.
The only way I got this resolved was by typing in the command "bgp
redistribute-internal" under R1's BGP process.
I was under the impression that when redistributing BGP into any IGP, the
"redistribute bgp x" was sufficient. But what the following link states is
that if you wish to redistribute IBGP routes, the above mentioned command
must also be used.
http://www.cisco.com/univercd/cc/td/doc/product/software/ios121/121cgcr/ip_r
/iprprt2/1rdbgp.htm#xtocid17
Can anyone shed some light on this it terms of the functionality of this
command. Essentially, what I am trying to say is that prior to today, i was
under the impression that "redistribute bgp x" was the ONLY command needed
?!
Thanks in advance,
Raj.
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