From: yakout esmat (yesmat@xxxxxxxxxxxxxx)
Date: Tue Jul 23 2002 - 06:52:21 GMT-3
Ali Basha :)
By default the lf size for fst encap is 516, so you don't need to configure
that manually.
The significance behind this frame size for fst encap is to make sure that
your DLSW+ packets traversing LAN segments and WAN interfaces will not be
dropped.
If your lf size exceeds any of the MTU sizes along the path between source
and destination, your packets will be dropped and session will not be
established.
Before changing the default size to any thing bigger than 516 you need to be
aware of MTU's of interfaces between source and destination and make sure
that they can accommodate the bigger frame size (adding all the different
headers etc...)
The difference between fst and tcp encap is that tcp can fragment frames if
need be, while fst does not. That's why this issue might not of great
significance with tcp, even though it might still affect performance and
spped.
HTH
Yakout
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
Ali Fahmi
Sent: Tuesday, July 23, 2002 6:12 PM
To: ccielab@groupstudy.com
Subject: lf on dlsw promiscous mode
Hi All,
if router A connected to Router B and C , and I set dlsw on
router A to be "promiscous mode", and I set remote peer on
router B point to A with TCP encapsulation, and
Router C remote peer to Router A with FST encapsulation,
should I change the largest frame on router A local peer to
516 (with dlsw prom-peer-default command)??
thx,
Ali
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