From: Emmanuel Oppong (e-oppong@xxxxxxxxx)
Date: Thu Jun 27 2002 - 18:01:01 GMT-3
Guys/gals
I need your help on this one:
r1 and r2 are configured as dlsw peers. r1 has a host on e0 network. r2
has host-1 and host-2
on its to0 network. I want r1's host to communicate with only host-1 on r2.
MAC addresses for
the hosts area :
r1 host = 0000-8616-3F04
r2 host-1 = 0000-F669-5EE7
r2 host-2 = 0000-F669-5F25
My relevant config for r1 are:
r1:
dlsw local-peer peer-id 172.16.101.1 promiscuous
dlsw peer-on-demand-defaults dmac-output-list 700
dlsw bridge-group 1
!
access-list 700 permit 0000.6F96.7AE7 0000.0000.0000
!
int e0
bridge-group 1
!
bridge 1 protocol ieee
!
My questions are:
I have bitswapped the mac address of host-1 in the access-list. Is that the
right thing to do,
convert r2 host-1 from non-canonical to canonical? Even if it is right, how
does r1 associate
these 2 mac addresses? I am thinking that r1 receives a frame from r2 with
host-1 source mac address
in the noncanonical form, right? But how does r1 know that the canonical
form in the access-list
matches the host-1 source mac address coming from r2? Can someone explain
this?
What is the right way to configure thsi scenario?
Thanks.
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