From: Christopher Jarosz (cajarosz@xxxxxxxxx)
Date: Wed Apr 17 2002 - 22:20:16 GMT-3
Hi Kris !!
The rif is broken out this way, RRRB or in your example 05d0. The first
three digits describe the ring number (yes, 93 is correct), and the bridge
number follow (in this example 0 which indicates that there is no bridge
beyond this point) (Valid bridge numbers are 1 through f (1 through 15 in
decimal). a valid example of a rif would be 0201 05d0) Originates on ring
32 (20 hex) through bridge 1 (1 hex) and terminates in ring 93 (05d0) or
ring 32 --bridge 1 -- ring 93
I Hope this helps.....
chrisj
----- Original Message -----
From: "Kris Keen" <kkeen@bigpond.net.au>
To: <ccielab@groupstudy.com>
Sent: Wednesday, April 17, 2002 5:27 AM
Subject: RIF, please help
> Hi All,
>
> I seem to have reading the RIF statements going ok, my question is when
the
> Direction bit (0 for L to R) and (1 for R to L) is set to 1, how do you
read
> it? You start from the FAR right and go backwards towards the left
correct?
>
> if I have 05D0 in my RD field, that tells me that its Ring 93 to
> destination, correct?
> Dennis explains this is Ring 93 to Bridge 1. I do not understand
>
> Please help
>
> Regards
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