From: Todd Carswell (acarswell@xxxxxxxxx)
Date: Thu Apr 04 2002 - 13:01:20 GMT-3
OOPS, I screwed up my custom queue example! Here it is again...
Example: 50% to IP, 25% IPX, 25% default
queue-list 1 protocol ip 1
queue-list 1 protocol ipx 2
queue-list 1 default 3
queue-list 1 queue 1 byte-count 6000
queue-list 1 queue 2 byte-count 3000
queue-list 1 queue 3 byte-count 3000
You see?! Nice and easy. I would not suggest trying to find any lowest
common denominators or normalizing anything. Keep it simple.
Todd
----- Original Message -----
From: <steven.j.nelson@bt.com>
To: <stan.zhang@verizon.com>; <Shaun.Wakelen@telindus.co.uk>;
<ccielab@groupstudy.com>
Sent: Thursday, April 04, 2002 9:24 AM
Subject: RE: Custom Queueing (Again)
> Thanks all,
>
> Better the devil you know then for me !!
>
> Steve
>
> -----Original Message-----
> From: Zhang, Stan [mailto:stan.zhang@verizon.com]
> Sent: 04 April 2002 15:14
> To: 'Shaun Wakelen'; Nelson,SJ,Steven,IVNH25 C; ccielab@groupstudy.com
> Subject: RE: Custom Queueing (Again)
>
>
> Steve,
>
> There is another way of doing that. Instead of using division, you can
use
> multiplication to derive the common denominator. Either way works fine,
and
> both methods take about equal amount of time. I would have to concur with
> Shaun and say stick with what you know best, it'll always be there when
you
> need it. Best of the luck.
>
>
> Stan Zhang
>
>
>
> -----Original Message-----
> From: Shaun Wakelen [mailto:Shaun.Wakelen@telindus.co.uk]
> Sent: Thursday, April 04, 2002 7:45 AM
> To: steven.j.nelson@bt.com; ccielab@groupstudy.com
> Subject: RE: Custom Queueing (Again)
>
>
> Steve
>
> That is the formula I was shown and now use. I have seen other ways posted
> on here, which seem more complicated, but that may be down to the fact I
> have not done it that way. Stick with what you know best. If you know it
> gives the correct result, and you have to use it, then the points are in
the
> bag!
>
> Shaun
>
> -----Original Message-----
> From: steven.j.nelson@bt.com [mailto:steven.j.nelson@bt.com]
> Sent: 04 April 2002 13:26
> To: ccielab@groupstudy.com
> Subject: Custom Queueing (Again)
>
>
> All
>
> What is the simplest formula for working out bandwidth allocation when
using
> custom queueing.
>
> I have been using the following but I am looking for a quicker way.
>
> Step 1 For each queue, divide the percentage of bandwidth you want to
> allocate to the queue by the packet size, in bytes. For example, assume
the
> packet size for protocol A is 1086 bytes, protocol B is 291 bytes, and
> protocol C is 831 bytes. We want to allocate 20 percent for A, 60 percent
> for B, and 20 percent for C. The ratios would be:
>
> 20/1086, 60/291, 20/831 or
>
> 0.01842, 0.20619, 0.02407
>
> Step 2 Normalize the numbers by dividing by the lowest number:
>
> 1, 11.2, 1.3
>
> The result is the ratio of the number of packets that must be sent so that
> the percentage of bandwidth that each protocol uses is approximately 20,
60,
> and 20 percent.
>
> Step 3 A fraction in any of the ratio values means that an additional
packet
> will be sent. Round up the numbers to the next whole number to obtain the
> actual packet count.
>
> In this example, the actual ratio will be 1 packet, 12 packets, and 2
> packets.
>
> Step 4 Convert the packet number ratio into byte counts by multiplying
each
> packet count by the corresponding packet size.
> In this example, the number of packets sent is one 1086-byte packet,
twelve
> 291-byte packets, and two 831-byte packets or
> 1086, 3492, and 1662 bytes, respectively, from each queue. These are the
> byte counts you would specify in your custom
> queueing configuration.
>
> Step 5 To determine the bandwidth distribution this ratio represents,
first
> determine the total number of bytes sent after all three queues are
> serviced:
>
> (1 x 1086) + (12 x 291) +(2 x 831) = 1086 + 3492 + 1662 = 6240
>
> Step 6 Then determine the percentage of the total number of bytes sent
from
> each queue:
>
> 1086/6240, 3492/6240, 1662/6240 = 17.4, 56, and 26.6 percent
>
> As you can see, this is close to the desired ratio of 20/60/20.
>
>
>
> Steve Nelson
> Customer Engineer
> BT Ignite- National Solutions
> T: +44 (0)1422 338881 M: +44 (0)7811 944172
> e-mail: steven.j.nelson@bt.com
> pp HW A170, PO Box 200(HOM-NZ), London, N18 1ZF
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