From: Lionel Florit (lflorit@xxxxxxxxx)
Date: Thu Mar 21 2002 - 04:43:56 GMT-3
Leonardo,
the way I see it is (in your example)
IP=2xIPX=10xDLSw
therefore a byte count of 1500 for DLSW, 15000 for ip, 7500 IPX should do it...
Lionel
At 02:44 AM 3/21/2002 -0300, Leonardo Pereira wrote:
>Hello guys !!!
>
>I've already understand how to calculate the byte-count to use with custom
>queuing. Now I want to know how I get the packet sizes for the protocols.
>
>Let's imagine I have to calculate the byte-count for IP, IPX and DLSW in
>the following way
>
>IP = 60 % of bandwidth
>IPX = 30 % of bandwidth
>DLSW = 10 % of bandwidth
>
>How can I know the packet size for these protocols ?
>
>To be more specific, what should I expect about this ? Should I have these
>numbers on my mind or they will be given ? And before someone claim about
>NDA, I don't want to know how these kind of question is presented at the
>exam.
>
>I am asking because at the books I read about this subject I couldn't find
>a scenario that ask me to calculate byte-count. All the examples already
>had the byte-count calculated.
>
>To finish, If someone has a good source for the protocol's packet size,
>please send it to me.
>
>Regards,
>Leonardo.
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