From: Lab Candidate (labccie@xxxxxxxxx)
Date: Thu Feb 14 2002 - 16:43:38 GMT-3
I concur. I've read Doyle's V1 and can't find answers to that.
--- "Xu, James" <james.xu@eds.com> wrote:
> Ross:
>
> Trust me, you will not be able to answer this question by reading through
> Doyle. I have been reading through it a couple of times.
>
> As far as your last comment, a CCIE may not be able to answer this question
> clearly. If you think it is easy, give a try!
>
> Like what I said, I am puting myself in beating position. :-)
>
> James
> -----Original Message-----
> From: RPF [mailto:rpf@multilayer.co.uk]
> Sent: Thursday, February 14, 2002 2:09 PM
> To: Xu, James; ccielab@groupstudy.com
> Subject: RE: How route redistribution EXACTLY works --- need
> confirmation
>
>
> James,
>
> In my opinion, it would probably be beneficial to read Doyle, Vol I from
> Cisco press, as the amount of info you need to know I don't think can be
> summarized in a few sentences.
>
> If you want CCIE, you need to read it anyhow. :-)
>
> Ross.
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> Xu, James
> Sent: 14 February 2002 18:44
> To: 'Todd Carswell'; ccielab@groupstudy.com
> Subject: RE: How route redistribution EXACTLY works --- need
> confirmation
>
>
> Todd:
>
> You are right, I am looking for answers about the "core mechanism" of the
> redistribution process. The points you presented are well valid.
>
> Here I am puting up a stroke man to let everyone to punch on, hopefully on
> the way, we all can get complete understanding. I, personally, didnot find
> much public documentaion to explain this.
>
> Some points I am going after are :
>
> 1). does the routing process pick routes out of routing database or out of
> routing table to do the redistribution? I am a believer of the former. But I
> would like some input on this, documentation even better.
> 2). does, in fact, the split-horizon rule applies here. It is my experience
> let me believe so. Further confirmation needed.
> 3). if possible if someone can post the algorithm related to the
> redistribution.
>
> Just a little more for chewing.
>
> James
>
> -----Original Message-----
> From: Todd Carswell [mailto:acarswell@nc.rr.com]
> Sent: Thursday, February 14, 2002 1:04 PM
> To: Xu, James; ccielab@groupstudy.com
> Subject: Re: How route redistribution EXACTLY works --- need
> confirmation
>
>
> Your description of the process sounds correct to me. That description is a
> "10,000 foot view" of redistribution.
>
> The tricky part of redistribution is two-fold:
>
> 1. You have to make sure that the metrics from one protocol are distributed
> properly into another. (i.e. hop-count in RIP translated into the OSPF
> metric.)
>
> 2. If you're redistributing from a classFUL protocol into a classLESS
> protocol (RIP to OSPF), you have to deal with classful networks not being
> visible in the classless domain.
>
> Somebody please beat me about the head and shoulders if I've got it wrong or
> if I've omitted something. :-)
>
> Todd Carswell
>
>
>
>
> ----- Original Message -----
> From: "Xu, James" <james.xu@eds.com>
> To: <ccielab@groupstudy.com>
> Sent: Thursday, February 14, 2002 11:57 AM
> Subject: How route redistribution EXACTLY works --- need confirmation
>
>
> > All:
> >
> > It has been and still puzzling me how a routing process pick routes and
> > redistribute them into another routing process and vice versa? As an
> > example, mutual redistribution between RIP and OSPF in a router:
> >
> > Here is my experience and explanation:
> >
> > 1). The RIP process picks all RIP routes inside its database, and
> > redistributes these routes into OSPF routing process.
> > 2). OSPF process picks all OSPF routes in the OSPF database, and
> > redistributes these routes into RIP routing process.
> >
> > During the redistribution, the split-horizon rule appies, meaning the
> newly
> > redistributed routes from RIP into OSPF will not be redistributed back
> into
> > RIP right away, and vice versa.
> >
> > Any input are appreciated, especially some links for this mechnism.
> >
> > James
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