From: Phil (ciscostudent1@xxxxxxxxxxxx)
Date: Sat Dec 08 2001 - 11:15:55 GMT-3
If you have a port with portfast enabled when you connect it to another switch
port it will be automatically placed in disable, unless that other port os also
configured with portfast enabled (and in this case they will not block and a l
oop will occur).
Phil.
Taz Kazam <taz_kazam@yahoo.co.uk> escreveu: Thanks Francois
I managed to find out. I think that the Cat1900 has
the ports status set to PORTFAST by default (command:
start-forwarding), hence, it removes the foward delay
time (15+15) = 30 sec, only using MaxAge = 20 sec.
If you configure the port with no start-forwarding
i.e. disable the PORTFAST, it then takes the 50
seconds to change over.
Thanks you you reply.
Taz.
--- Rivron Francois
wrote: > Hello,
> my think is as the switch is able to detect a fault
> at a physical level, the
> port state of the redondant link is move directly to
> listening state. So the
> redondant path should be on in 30s.
>
> Francois
>
> > -----Message d'origine-----
> > De: Taz Kazam [SMTP:taz_kazam@yahoo.co.uk]
> > Date: vendredi 7 dicembre 2001 10:38
> > @: thegroup
> > Objet: Spantree Timer
> >
> > Can anyone help.
> >
> > I've step up four 1900 Catalyst switch in a loop,
> to
> > test spanning tree. One port changes its state to
> > blocking, as I expected, however, when I take the
> > cable out of the non-redundant path, which cause
> the
> > redundant path to change from blocking to
> fowarding -
> > it does, but it only take 20 seconds. From my
> reading
> > this should take 50 seconds (15sec fwd delay -
> 20sec
> > MaxAge) Blocking -----15-----Listen---
> > 15-----Learning----20------Fowarding. Im using the
> > default factory settings!
> >
> > Anyone can help?
> >
> > Taz.
> >
> >
>
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