From: Jay Hennigan (jay@xxxxxxxx)
Date: Mon Oct 29 2001 - 23:09:43 GMT-3
On Tue, 30 Oct 2001, Jason Sinclair wrote:
> Cliff,
>
> Try this:
>
> Access-list 101 permit ip 158.168.0.0 0.0.254.255 any
>
> As you know to make the numbers even you must have the last bit of the third
> octet off, but don't care about the rest (eg
> 00000000.00000000.11111110.11111111)
But the task was:
I'm running OSPF to EIGRP redistribution and want to
advertise a group of class B subnets. 158.168.1.0 through
158.168.92.0. However odd number subnets need not be advertised.
EG. Advertise 158.168.2.0 and 158.168.4.0 through...
but not 158.168.3.0 or 158.168.5.0 etc, etc.
Now, this has the typical error that one sees in a lot of practice
scenarios of counting from 1 instead of 0. Assuming that the task is
really the even /24 subnets within the range of 158.168.0.0 through
158.168.95.255, which aligns things a bit better,
access-list 101 permit ip 158.168.0.0 0.0.62.255 any
access-list 101 permit ip 158.168.64.0 0.0.30.255 any
would do it. Of course you could also use a standard access list.
To answer the question as stated starting at 151.168.1.0 and including
only through 158.168.92.0 would require four lines according to my
thinking. I'll let someone else post the solution.
-- Jay Hennigan - CCIE #7880 - Network Administration - jay@west.net NetLojix Communications, Inc. - http://www.netlojix.com/ WestNet: Connecting you to the planet. 805 884-6323
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