From: Bob Chahal (bob.chahal@xxxxxxxxxxxx)
Date: Tue Aug 28 2001 - 06:29:27 GMT-3
I don't understand how if the LF is smaller that the MTU, then TCP will
fragment. Surely when the LF is greater than the MTU then TCP fragments???
----- Original Message -----
From: "Zeng Puyang" <zbridge98@yahoo.com>
To: <ccielab@groupstudy.com>
Sent: Tuesday, August 28, 2001 5:22 AM
Subject: dlsw lf question
> Hi, group:
>
> ring1-------R1<---dlsw--->R2----ethernet
>
> I always see (lf 1500) in the dlsw remote-peer command from cisco's
example and ccie power session. But when read the design guide of the dlsw,
I think it's not neccesary, at least for the TCP encapsulation. Could anyone
make this clear for me?
>
> The following is from the design guide:
http://www.cisco.com/warp/public/cc/pd/ibsw/ibdlsw/prodlit/dlsw4_rg.htm
>
> In general, when using TCP encapsulation, you probably will not need to
change the largest frame size because TCP
> fragments the frame size according to the MTU. For example, if the LF is
smaller than the MTU, then TCP will fragment each packet and send them in
sections across the WAN. If the LF is larger than the MTU, then individual
packets will be placed into the TCP/IP frame.
>
>
> Regards
>
> Zeng Puyang
>
> |:"f
> |g-J +~7&!"\"fv7,1+a6Zy
> _rj(}J&
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