From: perkinsr@xxxxxxxxxxxxxx
Date: Thu Aug 16 2001 - 18:14:38 GMT-3
This is what I think it should be:
mincir=128k
cir=256k
bc=256k/8=32k
be=0
This says you will not go below 128k, and you will shoot for 256k unless you
are getting BECNs. The bc is you cir/tc, and tc is ussually 8. be is how
many bits beyond your cir you want to go, but by using 256 as your cir you
keep this at 0.
I suppose you could also do it
mincir=128k
cir=128k
bc=16k
be=128k
I haven't seen it done this way, but I don't see why it wouldn't work. This
is tough to simulate as a router-frame switch will not generate BECNs to
activate the traffic shaping.
Ray
-----Original Message-----
From: Atakan San [mailto:asan@cisco.com]
Sent: Thursday, August 16, 2001 1:58 PM
To: ccielab@groupstudy.com
Subject: Frame-Relay Traffic-Shaping stuff
Hello Group,
I have an easy-looking but a little bit confusing FR traffic-shaping
question.
The requirement is
128K CIR
256K Burst size
Some people says option 1 some people says option 2 is correct...
Can you confirm me the right one ?
I cut the irrelevant parts of the configs. Here we go:
Option 1:
map-class frame-relay atakan1
frame-relay cir 128000
frame-relay bc 16000
frame-relay be 112000
Option 2:
map-class frame-relay atakan1
frame-relay cir 128000
frame-relay bc 16000
frame-relay be 144000
Thanks,
Atakan
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