From: Luke (luke.mendoza@xxxxxxxx)
Date: Sat Jun 16 2001 - 22:23:16 GMT-3
ok,
I am trying to understand SR/TLB with relation to DLSW...
Ethernet 0 ---------
R1 ------------------------------------------------R2 --------------------to
ken ring 0
|
|
|
token Ring 0
R1
source-bridge ring-group 250
source-bridge transparent 250 33 3 15
dlsw local-peer peer-id 10.1.1.1 promisc
dlsw bridge-group 15
bridge 15 protocol ieee
int ethernet 0
bridge-group 15
int tokenRing 0
ring-speed 16
source-bridge 100 2 250
source-bridge spanning
R2
source-bridge ring-group 500
dlsw local-peer peer-id 10.1.1.2
dlsw remote-peer 0 tcp 10.1.1.1
int tokenRing 0
ring-speed 16
source-bridge 200 1 500
source-bridge spanning
------------------------------------------------------------
Comments --------------------------------------------------
so I understand that if I had pc hosts attached to the Ethernet and token
ring interfaces of R1. Then DLSW+ is not needed for communicated but rather
translational bridging. I believe the configuration for R1 is correct. But
what if on R1 I put a static "ICANREACH" for an imaginary ethernet host.
I would put the command "dlsw icanreach mac-address xxxx.xxxx.xxxx " where x
is an ethernet mac-address
would I have to bit-swap this icanreach statement to a token ring format? I
don't believe that dlsw+ will do the bit swap automatically so that R2's
Token Ring host will be able to recognize the ethernet host.
To make this work, I believe I have to bit swap the ethernet host... so the
command would be "dlsw icanreach mac-address yxyx.yxyx.yxyx" where "yx" is
the bit swapped conversion of the "x" mac-address.
Please tell me if I am correct in my understanding. Do I also need to bit
swap between ethernet and token ring of R1? I think R1 would do that...
I would appreciate your comments !
Luke
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