From: Michael Davis (miked@xxxxxxxxxx)
Date: Tue May 22 2001 - 14:07:17 GMT-3
I think this is where you would use port-lists, no?
Mike
#7303
----- Original Message -----
From: "Choon, Raymond ()" <rchoon@att.com>
To: "'Padhu (LFG)'" <padhu@steinroe.com>; "'RAMIL'" <ramil@SkiBuff.com>;
"Theodore TZEVELEKIS" <theodore_tzevelekis@yahoo.com>;
<ccielab@groupstudy.com>
Cc: <gorrior@yahoo.com>
Sent: Tuesday, May 22, 2001 12:33 PM
Subject: RE: 2 dlsw peers. On both you have Ethernet and TR
> Padhu,
>
> I second your solution. This is what I would do.
>
> Raymond
>
> -----Original Message-----
> From: Padhu (LFG) [mailto:padhu@steinroe.com]
> Sent: Tuesday, May 22, 2001 11:41 AM
> To: 'RAMIL'; Theodore TZEVELEKIS; ccielab@groupstudy.com
> Cc: gorrior@yahoo.com
> Subject: RE: 2 dlsw peers. On both you have Ethernet and TR
>
>
> Just my 2c
>
> R1--------------R2
> ETh ETH
> TR TR
> On R1 and R2 , assign ip to ETH and TR interfaces and complete the dlsw
> configurations
> create a bridge group for ETh and Ring list for TR on both R1 and R2
> respectively.
> Create the remote peers on R1 with bgroup as the local target pointing to
> R2's ethernet as peer
> repeat this 3 more times for the 3 other interfaces.
>
> Somone correct me if this wouldn't work.
>
> Cheers,Padhu
>
>
>
> -----Original Message-----
> From: RAMIL [mailto:ramil@SkiBuff.com]
> Sent: Tuesday, May 22, 2001 10:35 AM
> To: Theodore TZEVELEKIS; ccielab@groupstudy.com
> Cc: gorrior@yahoo.com
> Subject: Re:
>
>
> border peers?
>
> ----- Original Message -----
> From: "Theodore TZEVELEKIS" <theodore_tzevelekis@yahoo.com>
> To: <ccielab@groupstudy.com>
> Cc: <gorrior@yahoo.com>
> Sent: Tuesday, May 22, 2001 11:28 AM
>
>
> > Suppose you have 2 dlsw peers. On both you have
> > Ethernet and TR.
> >
> > However, you only want the 2 ethernets to communicate
> > with eachother and the two TR with eachother.
> >
> > In other words, no TR traffic should be seen on either
> > ethernet and no ethernet traffic should be seen on
> > either TR.
> >
> > Any ideas about how to do this?
> >
> > Please reply to all.
> >
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