From: Marcio Pilotto (marcio.pilotto@xxxxxxxxxxxxxx)
Date: Fri Apr 20 2001 - 12:04:05 GMT-3
on inverse mask you should not use even number. Only odd, like 0.0.7.255 or
0.0.3.255.
Marcio Pilotto
Network Design Engineer
Intelig Telecomunicagues Ltda
Praia de Botafogo, 440 - 120 andar
Tel.: + 55 21 536 0880
Mobile: +55 21 97 65 65 23
Fax: +55 21 536 0903
marcio.pilotto@intelig.net.br <mailto:marcio.pilotto@intelig.net.br>
-----Original Message-----
From: Shane Miles [mailto:smiles@ftdata.com]
Sent: sexta-feira, 20 de abril de 2001 11:29
To: 'ccielab@groupstudy.com'
Subject: RE: wildcard mask problem
When I try 0.0.6.255 I get the follwing:
Router(config-router)#network 192.168.2.0 0.0.6.255 area 0
OSPF: Invalid address/mask combination (discontiguous mask)
Router(config-router)#
What am I missing?
-----Original Message-----
From: Rick Burts [mailto:burts@mentortech.com]
Sent: Thursday, April 19, 2001 2:03 PM
To: louie kouncar
Cc: 'David Bader'; 'CCIE Lab'; 'Chuck Larrieu'
Subject: RE: wildcard mask problem
This is not correct.
There is a requirement that the ones be contiguous in a subnet mask but
not a requirement in an inverse mask such as this. The 0.0.6.255 is a
somewhat more sophisticated and more efficient solution, and it would
work. The original question asked how to combine network statements
for network 2 and network 4 in an OSPF network statement. Any solution
that combines into fewer statements will include some excess networks.
The .6 mask will include 2 excell networks (0 and 6) while the 7 mask
will include 6 excess networks (0,1,3,5,6,7). Both solutions are valid.
One is slightly optimized.
Rick
Rick Burts, CCSI CCIE 4615 burts@mentortech.com
Mentor Technologies 240-568-6500 ext 6652
133 National Business Parkway 240-568-6515 fax
Annapolis Junction, Md 20701
Chesapeake Network Solutions has now become Mentor Technologies.
Mentor Technologies is a certified Cisco Training Partner and also
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We offer most of the Cisco training courses.
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We also provide network consulting services including
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We have 21 CCIEs on our staff.
We offer the breakthrough VLAB remote access technology for
access to practice configuration on real equipment.
On Thu, 19 Apr 2001, louie kouncar wrote:
> Dave,
>
> You are right, This should be 192.168.0.0 0.0.7.255, 6 in the third octet
> will break the subnetting rules and will not work, the reason is if you do
> the 255-248 you will get 7 and not 6. I am not aware of a 255.255.249.0
> mask, which will be the case if this was 0.0.6.0
>
> I hope I am right.....
>
>
> Thanks
>
>
> Louie J. Kouncar (CCIE)/Written
> TCO3 Senior Data Center Engineer
> UUNET
> W-703-343-6645
> C-703-304-2460
>
>
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> David Bader
> Sent: Thursday, April 19, 2001 12:08 PM
> To: CCIE Lab; Chuck Larrieu
> Subject: AW: wildcard mask problem
>
>
> This wouldn't work, because it it not a contignuous wildcard:
> 00000000.00000000.00000110.11111111
>
> dave
>
> -----Urspr|ngliche Nachricht-----
> Von: Chuck Larrieu [mailto:chuck@cl.cncdsl.com]
> Gesendet: Donnerstag, 19. April 2001 08:40
> An: David Bader
> Betreff: RE: wildcard mask problem
>
>
> Try 192.168.0.0 0.0.6.255
>
> Tell me what that covers.
>
> to quote a sage - think different.
>
> Chuck
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> David Bader
> Sent: Wednesday, April 18, 2001 11:27 PM
> To: "louie kouncar" <lkouncar@UU.NET>
> Subject: RE: wildcard mask problem
>
> This is correct, but you can only summarise 192.168.0.0 - 192.168.7.255.
so
> you either summarise all of them, or you need two statements.
>
> Dave
>
>
> > Bruce,
> >
> > you are totally correct, my mistake, I was more concerned with the third
> > octet of the wildcard mask since that was where the question was
directed
> > at.
> >
> >
> > it should be 192.168.0.0 0.0.7.255 area 0
> >
> >
> >
> > Thanks
> >
> >
> > Louie J. Kouncar (CCIE)/Written
> > TCO3 Senior Data Center Engineer
> > UUNET
> > W-703-343-6645
> > C-703-304-2460
> >
> >
> >
> > -----Original Message-----
> > From: Bruce Williams [mailto:bruce@williamsnetworking.com]
> > Sent: Wednesday, April 18, 2001 9:37 PM
> > To: louie kouncar; 'Bob Dixon'; ccielab@groupstudy.com
> > Subject: Re: wildcard mask problem
> >
> >
> > Louie,
> >
> > Please correct me if I am wrong. Should not the summarized network
address
> > be 192.168.0.0 because 192.168.2.0 does not summarize 192.168.4.0.
> >
> > The third octet for both networks.
> > 192.168.2.0 is 00000010
> > 182.168.4.0 is 00000100
> >
> > If that is not correct, could you please explain.
> >
> > Bruce
> > bruce@williamsnetworking.com
> >
> >
> > ----- Original Message -----
> > From: "louie kouncar" <lkouncar@UU.NET>
> > To: "'Bob Dixon'" <bobdixon@mediaone.net>; <ccielab@groupstudy.com>
> > Sent: Wednesday, April 18, 2001 9:24 PM
> > Subject: RE: wildcard mask problem
> >
> >
> > > Ops,
> > >
> > > That should be 0.0.7.255
> > >
> > > sorry for the typo
> > >
> > > Louie J. Bouncer (CCIE)/Written
> > > TCO3 Senior Data Center Engineer
> > > UUNET
> > > W-703-343-6645
> > > C-703-304-2460
> > >
> > >
> > >
> > > -----Original Message-----
> > > From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> > > Bob Dixon
> > > Sent: Wednesday, April 18, 2001 8:38 PM
> > > To: ccielab@groupstudy.com
> > > Subject: wildcard mask problem
> > >
> > >
> > > Folks,
> > >
> > > I should know how to do this, but I can't seem to get it.
> > >
> > > Question:
> > > take the following:
> > > network 192.168.2.0 0.0.0.255 area 0
> > > network 192.168.4.0 0.0.0.255 area 0
> > >
> > > and create one network statement that summarizes the two.
> > >
> > > Thanks,
> > > Bob
> > > **Please read:http://www.groupstudy.com/list/posting.html
> > > **Please read:http://www.groupstudy.com/list/posting.html
> > **Please read:http://www.groupstudy.com/list/posting.html
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