From: Chuck Larrieu (chuck@xxxxxxxxxxxxx)
Date: Wed Apr 18 2001 - 22:40:31 GMT-3
I believe that 192.168.0.0 0.0.6.255 provides a bit of a finer tune, if
you will excuse the pun. It includes networks 0,2,4, and 6 whereas the
0.0.7.255 permits 1,3,5, and 7 networks in addition to the even numbered
networks.
I asked off line if there were any particular restrictions to the
summarization, as the original post was ambiguous. Without something more
specific, even 0.0.255.255 does the job requested.
Chuck
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
louie kouncar
Sent: Wednesday, April 18, 2001 6:24 PM
To: 'Bob Dixon'; ccielab@groupstudy.com
Subject: RE: wildcard mask problem
Ops,
That should be 0.0.7.255
sorry for the typo
Louie J. Bouncer (CCIE)/Written
TCO3 Senior Data Center Engineer
UUNET
W-703-343-6645
C-703-304-2460
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
Bob Dixon
Sent: Wednesday, April 18, 2001 8:38 PM
To: ccielab@groupstudy.com
Subject: wildcard mask problem
Folks,
I should know how to do this, but I can't seem to get it.
Question:
take the following:
network 192.168.2.0 0.0.0.255 area 0
network 192.168.4.0 0.0.0.255 area 0
and create one network statement that summarizes the two.
Thanks,
Bob
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