From: Bruce Williams (bruce@xxxxxxxxxxxxxxxxxxxxxx)
Date: Wed Apr 18 2001 - 22:37:05 GMT-3
Louie,
Please correct me if I am wrong. Should not the summarized network address
be 192.168.0.0 because 192.168.2.0 does not summarize 192.168.4.0.
The third octet for both networks.
192.168.2.0 is 00000010
182.168.4.0 is 00000100
If that is not correct, could you please explain.
Bruce
bruce@williamsnetworking.com
----- Original Message -----
From: "louie kouncar" <lkouncar@UU.NET>
To: "'Bob Dixon'" <bobdixon@mediaone.net>; <ccielab@groupstudy.com>
Sent: Wednesday, April 18, 2001 9:24 PM
Subject: RE: wildcard mask problem
> Ops,
>
> That should be 0.0.7.255
>
> sorry for the typo
>
> Louie J. Bouncer (CCIE)/Written
> TCO3 Senior Data Center Engineer
> UUNET
> W-703-343-6645
> C-703-304-2460
>
>
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> Bob Dixon
> Sent: Wednesday, April 18, 2001 8:38 PM
> To: ccielab@groupstudy.com
> Subject: wildcard mask problem
>
>
> Folks,
>
> I should know how to do this, but I can't seem to get it.
>
> Question:
> take the following:
> network 192.168.2.0 0.0.0.255 area 0
> network 192.168.4.0 0.0.0.255 area 0
>
> and create one network statement that summarizes the two.
>
> Thanks,
> Bob
> **Please read:http://www.groupstudy.com/list/posting.html
> **Please read:http://www.groupstudy.com/list/posting.html
**Please read:http://www.groupstudy.com/list/posting.html
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