From: Bruce Williams (bruce@xxxxxxxxxxxxxxxxxxxxxx)
Date: Wed Apr 18 2001 - 21:59:25 GMT-3
The two network address have the first 5 bits of the third octet in common.
The wildcard mask is the sum of the bits that they do not have in common in
the third octet; 4, 2 ,1 and then the sum of all the bits in the last octet.
network 192.168.0.0 0.0.7.255 area 0
Bruce
mailto:bruce@williamsnetworking.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
Bob Dixon
Sent: Wednesday, April 18, 2001 8:38 PM
To: ccielab@groupstudy.com
Subject: wildcard mask problem
Folks,
I should know how to do this, but I can't seem to get it.
Question:
take the following:
network 192.168.2.0 0.0.0.255 area 0
network 192.168.4.0 0.0.0.255 area 0
and create one network statement that summarizes the two.
Thanks,
Bob
**Please read:http://www.groupstudy.com/list/posting.html
**Please read:http://www.groupstudy.com/list/posting.html
This archive was generated by hypermail 2.1.4 : Thu Jun 13 2002 - 10:29:50 GMT-3