Re: OSPF Redistribution Challenge

From: Bill Dellamar (wdellamar@xxxxxxxxx)
Date: Mon Jan 22 2001 - 14:19:24 GMT-3


   
I don't have a rack to test this, but this would be my
first guess.

How about this on R3:
router ospf 1
default-information-originate route-map gen-default
!
route-map gen-default permit 10
match ip address 1
!
access-list 1 permit 135.5.192.0 0.0.0.3

Bill

--- Mike McSpedon <mike@mentortech.com> wrote:
> Here's a challenge:
>
> r1e0===e0r2s0====s1r3s0=======s1r4e0
>
> r1e0: 170.10.1.1 /24
> r2e0: 170.10.1.2 /24
> r2s0:170.10.255.1 /30
> r3s1:170.10.255.2 /30
> r3s0: 135.5.192.1 /30
> r4s1: 135.5.192.2 /30
> r4e0: 135.5.112.0 /24
>
> Loopbacks:
> r3: 192.168.3.1
> r4: 192.168.4.1
>
> 1. Routers 1, 2, and the 3 are routing IP via ISIS.
> 2. OSPF is running only on the serial link between
> routers 3 and 4 and on
> the Ethernet on r4 (all Area 0).
> 3 . Perform mutual redistribution between ISIS and
> OSPF on r3 .
> 4. Advertise a default route to from r3 to r4 if
> AND ONLY if r2 is
> reachable. Do not use a default route in the ISIS
> domain. Only advertise
> the address above from the ISIS domain to the OSPF
> domain.
>
> The answer is on the CD.
>
> Enjoy!
> -Mike
>
>



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